创建一个范围在(0,1)之间的长度为12的等差数列，创建[1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024]等比数列代码

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Q：创建一个范围在(0,1)之间的长度为12的等差数列，创建[1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024]等比数列代码。

A：可以使用numpy库中的linspace函数来创建等差数列，代码如下：

import numpy as np

arithmetic_seq = np.linspace(0, 1, 12)
print(arithmetic_seq)

geometric_seq = [2**i for i in range(11)]
geometric_seq.insert(0, 1)
print(geometric_seq)

相关问题

创建一个范围在(0,1)之间的长度为12的等差数列

Sure, the arithmetic sequence with 12 terms and values between 0 and 1 is: 0.083, 0.166, 0.25, 0.333, 0.416, 0.5, 0.583, 0.666, 0.75, 0.833, 0.916, 1.

4. 创建一个范围在(0,1)之间的长度为12的等差数列；

0.09090909090909091, 0.18181818181818182, 0.2727272727272727, 0.36363636363636365, 0.45454545454545453, 0.5454545454545454, 0.6363636363636364, 0.7272727272727273, 0.8181818181818182, 0.9090909090909091, 1.0