数字按位数排序Java怎么实现
时间: 2024-09-06 10:07:34 浏览: 40
在Java中对数字按照位数进行排序,通常需要自定义一个Comparator来比较整数的每一位。这里提供一种简单的实现方法:
```java
import java.util.Arrays;
import java.util.Comparator;
public class BitwiseSort {
public static void main(String[] args) {
int[] numbers = {57, 14, 69, 82, 27};
Arrays.sort(numbers, new Comparator<Integer>() {
@Override
public int compare(Integer a, Integer b) {
return Long.compare(a.bitCount(), b.bitCount());
}
});
System.out.println("Sorted numbers: " + Arrays.toString(numbers));
相关问题
Java怎么实现输入一串数字并对数字按位排序
在Java中,你可以使用Scanner类获取用户输入的一串数字,然后通过遍历和自定义排序方式进行按位排序。这里是一个简单的示例:
```java
import java.util.Arrays;
import java.util.Scanner;
import java.util.Comparator;
public class BitwiseSortUserInput {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("请输入一组数字,用逗号分隔:");
String input = scanner.nextLine();
String[] numberStrings = input.split(",");
int[] numbers = new int[numberStrings.length];
// 将字符串转换成整数并排序
for (int i = 0; i < numberStrings.length; i++) {
numbers[i] = Integer.parseInt(numberStrings[i]);
}
Arrays.sort(numbers, new Comparator<Integer>() {
@Override
public int compare(Integer a, Integer b) {
return Long.compare(a.bitCount(), b.bitCount());
}
});
System.out.println("按位数排序后的数字: " + Arrays.toString(numbers));
吸血鬼数字是指位数为偶数的数字,可以由一对数字相乘而得到,而这对数字各包含乘积的一半位数的数字,其中从最初的数字中选择的数字可以任意排序。以两个0结尾的数字是不允许的,例如,下列数字都是“吸血鬼”数字: 1260=21*60 1827=21*87 2187=27*81 写一个程序,找出4位数的所有吸血鬼数字Java代码
以下是一个Java程序,可以找出所有4位数的吸血鬼数字:
```java
public class VampireNumbers {
public static void main(String[] args) {
for (int i = 1000; i < 10000; i++) {
int a = i / 1000;
int b = (i / 100) % 10;
int c = (i / 10) % 10;
int d = i % 10;
if (checkVampireNumber(a, b, c, d, a, b, c, d)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, a, b, d, c)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, a, c, b, d)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, a, c, d, b)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, a, d, b, c)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, a, d, c, b)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, b, a, c, d)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, b, a, d, c)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, b, c, a, d)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, b, c, d, a)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, b, d, a, c)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, b, d, c, a)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, c, a, b, d)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, c, a, d, b)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, c, b, a, d)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, c, b, d, a)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, c, d, a, b)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, c, d, b, a)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, d, a, b, c)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, d, a, c, b)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, d, b, a, c)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, d, b, c, a)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, d, c, a, b)) {
System.out.println(i);
}
if (checkVampireNumber(a, b, c, d, d, c, b, a)) {
System.out.println(i);
}
}
}
public static boolean checkVampireNumber(int a, int b, int c, int d, int w, int x, int y, int z) {
int num1 = 10 * a + b;
int num2 = 10 * c + d;
int product = num1 * num2;
int firstHalf = 10 * w + x;
int secondHalf = 10 * y + z;
return product == firstHalf * secondHalf && product % 100 != 0;
}
}
```
该程序通过枚举所有可能的数字组合,并检查它们是否满足吸血鬼数字的定义来找出所有4位数的吸血鬼数字。
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