JAVA 1.传入设备的日常工作时间段(HH:mm-HH:mm;HH:mm-HH:mm;HH:mm-HH:mm) 1.传入某工序需要的工作时间(分) 2.传入这个设备空闲时间段如(HH:mm-HH:mm;HH:mm-HH:mm;HH:mm-HH:mm;HH:mm-HH:mm) 3.判断这个设备空闲时间段时间是否满足工序的工作时间需要 返回true或false 注意:设备满足工序的时间段必须是除休息时间段外的连续工作时间段
时间: 2023-08-06 18:09:35 浏览: 37
好的,让我来帮您解答这个问题。您可以按照以下步骤实现:
1. 将传入的设备日常工作时间段和空闲时间段拆分成多个时间段,并分别存储为列表,每个时间段包含开始时间和结束时间。
2. 遍历设备空闲时间段列表,对于每个时间段,判断是否有足够的时间来完成所需工作。如果有,则返回true,否则继续遍历。
3. 在判断时间段是否足够完成工作时,需要注意排除休息时间段。可以将休息时间段从设备日常工作时间段中去除,然后再进行计算。
以下是示例代码,供您参考:
```java
import java.util.ArrayList;
import java.util.List;
public class Device {
private List<TimePeriod> dailyWorkTime = new ArrayList<>();
private int workTimeNeeded;
private List<TimePeriod> freeTime = new ArrayList<>();
public Device(String dailyWorkTimeStr, int workTimeNeeded, String freeTimeStr) {
// 解析传入的时间段字符串,构造时间段列表
this.dailyWorkTime = parseTimePeriodList(dailyWorkTimeStr);
this.workTimeNeeded = workTimeNeeded;
this.freeTime = parseTimePeriodList(freeTimeStr);
}
public boolean canWork() {
// 去除休息时间段
List<TimePeriod> workTime = new ArrayList<>(dailyWorkTime);
for (TimePeriod free : freeTime) {
workTime = subtractTimePeriod(workTime, free);
}
// 遍历设备空闲时间段,判断是否有足够的时间完成工作
for (TimePeriod free : freeTime) {
List<TimePeriod> availableTime = intersectTimePeriod(workTime, free);
for (TimePeriod period : availableTime) {
if (period.duration() >= workTimeNeeded) {
return true;
}
}
}
return false;
}
// 解析时间段列表
private List<TimePeriod> parseTimePeriodList(String timeStr) {
List<TimePeriod> list = new ArrayList<>();
String[] parts = timeStr.split(";");
for (String part : parts) {
String[] times = part.split("-");
list.add(new TimePeriod(times[0], times[1]));
}
return list;
}
// 计算时间段交集
private List<TimePeriod> intersectTimePeriod(List<TimePeriod> list1, TimePeriod period) {
List<TimePeriod> result = new ArrayList<>();
for (TimePeriod p : list1) {
TimePeriod intersect = p.intersect(period);
if (intersect != null) {
result.add(intersect);
}
}
return result;
}
// 计算时间段差集
private List<TimePeriod> subtractTimePeriod(List<TimePeriod> list1, TimePeriod period) {
List<TimePeriod> result = new ArrayList<>();
for (TimePeriod p : list1) {
List<TimePeriod> subtract = p.subtract(period);
result.addAll(subtract);
}
return result;
}
}
class TimePeriod {
private int startHour;
private int startMinute;
private int endHour;
private int endMinute;
public TimePeriod(String start, String end) {
String[] startParts = start.split(":");
this.startHour = Integer.parseInt(startParts[0]);
this.startMinute = Integer.parseInt(startParts[1]);
String[] endParts = end.split(":");
this.endHour = Integer.parseInt(endParts[0]);
this.endMinute = Integer.parseInt(endParts[1]);
}
public int duration() {
return (endHour - startHour) * 60 + (endMinute - startMinute);
}
public TimePeriod intersect(TimePeriod other) {
int startHour = Math.max(this.startHour, other.startHour);
int startMinute = Math.max(this.startMinute, other.startMinute);
int endHour = Math.min(this.endHour, other.endHour);
int endMinute = Math.min(this.endMinute, other.endMinute);
if (startHour < endHour || (startHour == endHour && startMinute < endMinute)) {
return new TimePeriod(String.format("%02d:%02d", startHour, startMinute),
String.format("%02d:%02d", endHour, endMinute));
} else {
return null;
}
}
public List<TimePeriod> subtract(TimePeriod other) {
List<TimePeriod> result = new ArrayList<>();
if (this.startHour < other.startHour) {
result.add(new TimePeriod(String.format("%02d:%02d", this.startHour, this.startMinute),
String.format("%02d:%02d", other.startHour, other.startMinute)));
}
if (this.endHour > other.endHour) {
result.add(new TimePeriod(String.format("%02d:%02d", other.endHour, other.endMinute),
String.format("%02d:%02d", this.endHour, this.endMinute)));
}
return result;
}
}
```
您可以通过以下方式测试代码:
```java
public static void main(String[] args) {
Device device = new Device("08:00-12:00;13:00-17:00", 120, "09:00-11:00;13:30-15:30");
System.out.println(device.canWork()); // true
Device device2 = new Device("08:00-12:00;13:00-17:00", 120, "16:00-18:00");
System.out.println(device2.canWork()); // false
}
```
希望能帮助到您!