某班有 5 个学生,三门课（语文、数学、英语）。录入学生的信息并分别编写 3 个函数实现以下要求： (1) 求各门课的平均分; (2) 找出有两门以上不及格的学生,并输出其学号和不及格课程的成绩; (3) 找出三门课平均成绩在 85-90 分的学生,并输出其学号和姓名

以下是代码实现：

-- 学生信息表
local students = {
    {id = 1, name = "张三", chinese = 80, math = 90, english = 85},
    {id = 2, name = "李四", chinese = 75, math = 60, english = 70},
    {id = 3, name = "王五", chinese = 90, math = 85, english = 95},
    {id = 4, name = "赵六", chinese = 95, math = 80, english = 90},
    {id = 5, name = "钱七", chinese = 85, math = 70, english = 80},
}

-- 求各门课的平均分
function averageScore(subject)
    local sum = 0
    for _, student in ipairs(students) do
        sum = sum + student[subject]
    end
    return sum / #students
end

-- 找出有两门以上不及格的学生，并输出其学号和不及格课程的成绩
function failedStudents()
    local failedCount = 0
    for _, student in ipairs(students) do
        if student.chinese < 60 then
            failedCount = failedCount + 1
            print(student.id, "语文", student.chinese)
        end
        if student.math < 60 then
            failedCount = failedCount + 1
            print(student.id, "数学", student.math)
        end
        if student.english < 60 then
            failedCount = failedCount + 1
            print(student.id, "英语", student.english)
        end
        if failedCount >= 2 then
            break
        end
    end
end

-- 找出三门课平均成绩在 85-90 分的学生，并输出其学号和姓名
function goodStudents()
    for _, student in ipairs(students) do
        local average = (student.chinese + student.math + student.english) / 3
        if average >= 85 and average <= 90 then
            print(student.id, student.name)
        end
    end
end

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