if index==1: count = count_conditions( teacher_arr, lambda row: row[3] <24, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==2: count = count_conditions( teacher_arr, lambda row: row[3] >24 and lambda row: row[3] <30, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==3: count = count_conditions( teacher_arr, lambda row: row[3] >29 and lambda row: row[3] <35, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==4: count = count_conditions( teacher_arr, lambda row: row[3] >34 and lambda row: row[3] <40, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==5: count = count_conditions( teacher_arr, lambda row: row[3] >39 and lambda row: row[3] <45, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==6: count = count_conditions( teacher_arr, lambda row: row[3] >44 and lambda row: row[3] <50, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==7: count = count_conditions( teacher_arr, lambda row: row[3] >49 and lambda row: row[3] <55, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==8: count = count_conditions( teacher_arr, lambda row: row[3] >54 and lambda row: row[3] <60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==8: count = count_conditions( teacher_arr, lambda row: row[3] >54 and lambda row: row[3] <60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==9: count = count_conditions( teacher_arr, lambda row: row[3] >=60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass

你的问题是关于一个Python代码片段的，它根据条件计算教师人数。在这个代码片段中，有多个if语句，每个if语句都根据不同的年龄范围和其它条件计算教师人数。具体来说，如果index等于1，那么代码将统计年龄小于24岁、专任教师且科目为itme1的教师人数；如果index等于2，那么代码将统计年龄在24岁到30岁之间、专任教师且科目为itme1的教师人数；以此类推。需要提醒的是，代码片段中的每个lambda表达式都是用来筛选满足条件的行的。

相关问题

if index==1: count = count_conditions( teacher_arr, lambda row: row[3] <24, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==2: count = count_conditions( teacher_arr, lambda row: row[3] >24 and lambda row: row[3] <30, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==3: count = count_conditions( teacher_arr, lambda row: row[3] >29 and lambda row: row[3] <35, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==4: count = count_conditions( teacher_arr, lambda row: row[3] >34 and lambda row: row[3] <40, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==5: count = count_conditions( teacher_arr, lambda row: row[3] >39 and lambda row: row[3] <45, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==6: count = count_conditions( teacher_arr, lambda row: row[3] >44 and lambda row: row[3] <50, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==7: count = count_conditions( teacher_arr, lambda row: row[3] >49 and lambda row: row[3] <55, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==8: count = count_conditions( teacher_arr, lambda row: row[3] >54 and lambda row: row[3] <60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==8: count = count_conditions( teacher_arr, lambda row: row[3] >54 and lambda row: row[3] <60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==9: count = count_conditions( teacher_arr, lambda row: row[3] >=60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass 优化代码

您的代码可以通过使用循环和列表，来避免重复的代码。以下是一种重构方案：

age_ranges = [(0, 24), (24, 30), (30, 35), (35, 40), (40, 45), (45, 50), (50, 55), (55, 60), (60, 100)]
counts = []
for i, age_range in enumerate(age_ranges):
    if i == index - 1:
        count = count_conditions(teacher_arr, 
                                 lambda row: age_range[0] < row[3] < age_range[1], 
                                 lambda row: row[11] == item1, 
                                 lambda row: row[8] == '专任教师')
        counts.append(count)
    else:
        counts.append(0)

这样，您就可以通过循环和列表，避免重复的代码，并且可以更加清晰和易读。

if itme1 == '总计': count = count_conditions( teacher_arr, lambda row: row[9] == '学前' or row[9] == '小学', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '女': count = count_conditions( teacher_arr, lambda row: row[2] == '女', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '少数民族': count = count_conditions( teacher_arr, lambda row: row[11] != '汉族', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '在编人员': count = count_conditions( teacher_arr, lambda row: row[12] == '是', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count代码优化

:可以考虑将重复使用的代码封装成一个函数，以减少代码重复和提高代码可读性。例如：

def count_by_criteria(teacher_arr, criteria_func, filter_func):
count = count_conditions(teacher_arr, criteria_func, filter_func)
if count != 0:
sh_4149.cell(index1, index).value = count

然后使用这个函数来代替原本重复的代码，例如：

if itme1 == '总计':
count_by_criteria(teacher_arr, lambda row: row[9] == '学前' or row[9] == '小学', lambda row: row[8] == itme)
if itme1 == '女':
count_by_criteria(teacher_arr, lambda row: row[2] == '女', lambda row: row[8] == itme)
if itme1 == '少数民族':
count_by_criteria(teacher_arr, lambda row: row[11] != '汉族', lambda row: row[8] == itme)
if itme1 == '在编人员':
count_by_criteria(teacher_arr, lambda row: row[12] == '是', lambda row: row[8] == itme)

这样代码会更易读和易维护。