是的,帮我 用Matlab代码解决它
时间: 2024-03-22 13:39:38 浏览: 60
好的,下面是用Matlab求解该投资决策问题的代码:
```matlab
% 定义目标函数系数
f = [-1.15, 0, 0, -1.25, -1.4, 0, 0, 1.06, 0, 1.06, 0, 0, 0, 1.15, 1.06];
% 定义约束条件系数矩阵和右端向量
A = [1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0;
0, 1, 0, 0, 0, 0, 0, -1.06, 1.06, 0, 1, 0, 0, 0, 0;
1.15, 0, 0, 1.06, 0, 0, 0, 0, 0, 0, -1.06, 1.06, 0, 0, 0;
0, 1.15, 0, 0, 1.06, 0, 0, 0, 0, 0, 0, -1.06, 1.06, 0, 0;
0, 0, 1.15, -1.25, 0, 1.06, 0, 0, 0, 0, 0, 0, -1.06, 1.06, 0;
0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0;
0, 0, 0, 0, 0, 1, 0, 0, -1, 0, 0, 0, 0, 0, 0;
0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, -1, 0, 0, 0];
b = [10; 0; 0; 0; 0; 4; 3; 0];
% 定义变量下界和上界
lb = zeros(15, 1);
ub = [Inf; Inf; Inf; 4; 3; Inf; Inf; Inf; Inf; Inf; Inf; Inf; Inf; Inf; Inf];
% 求解线性规划问题
[x, fval, exitflag] = linprog(f, A, b, [], [], lb, ub);
% 输出结果
disp(['最大收益为:', num2str(-fval)]);
disp(['投资方案为:']);
disp(['项目1每年投资:', num2str(x(1)), ', ', num2str(x(2)), ', ', num2str(x(3)), ', ', num2str(x(4))]);
disp(['项目2投资:', num2str(x(5))]);
disp(['项目3投资:', num2str(x(6)), ', ', num2str(x(7)), ', ', num2str(x(8))]);
disp(['项目4每年投资:', num2str(x(9)), ', ', num2str(x(10)), ', ', num2str(x(11)), ', ', num2str(x(12)), ', ', num2str(x(13)), ', ', num2str(x(14))]);
disp(['年闲钱投资项目4:', num2str(x(15))]);
```
注:由于线性规划求解器的不同,可能会有细微的差别,但整体结果应该是一致的。
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