#include <iostream> #include <bitset> #include <algorithm> #include <cstring> #include <memory> using namespace std; //局部状态决定全局状态，第一行的状态决定全局，所以枚举2的六次方，上道题密码锁最左边就是局部，所以2次枚举 bitset<6> source[5],//初始灯 lights[5],//中间过程的灯 res[5],//结果的灯 line;//某一行的开关状态 void output(int t) { cout << "PUZZLE #" << t << endl; for (int i = 0; i < 5; i++) { for (int j = 0; j < 6; j++) { cout << res[i][j] << " "; } cout << endl; } } int main() { int t; cin >> t; for (int x = 1; x <= t; x++) { for (int i = 0; i < 5; i++) { for (int j = 0; j < 6; j++) { int m; cin >> m; source[i].set(j, m);//初始化 } } for (int n = 0; n < 64; n++) { for (int i = 0; i < 5; i++) lights[i] = source[i]; line = n;//n会自动转换为二进制000000,到111111，刚刚好就是我们所要枚举的全部状态 for (int i = 0; i < 5; i++) { res[i] = line; for (int j = 0; j < 6; j++) { if (line.test(j))//判断第j位是不是为1 { if (j > 0) lights[i].flip(j - 1); if(j<5) lights[i].flip(j + 1); lights[i].flip(j); } } if (i < 4)lights[i + 1] ^= line;//取异或，同为0，异为1； line = lights[i]; } if (lights[4].none()) { output(x); break; } } } return 0; }，你可以将上述代码变为ptyhon语言的吗，注意，不要导入任何库

可以将上述C++代码转换为Python代码。以下是转换后的Python代码：

class Bitset:
    def __init__(self, size):
        self.bits = [0] * size

    def set(self, index, value):
        self.bits[index] = value

    def test(self, index):
        return self.bits[index]

    def flip(self, index):
        self.bits[index] ^= 1

    def none(self):
        return sum(self.bits) == 0

def output(t):
    print(f"PUZZLE #{t}")
    for i in range(5):
        for j in range(6):
            print(res[i].test(j), end=" ")
        print()

t = int(input())
for x in range(1, t+1):
    source = [Bitset(6) for _ in range(5)]
    lights = [Bitset(6) for _ in range(5)]
    res = [Bitset(6) for _ in range(5)]
    
    for i in range(5):
        for j in range(6):
            m = int(input())
            source[i].set(j, m)

    for n in range(64):
        for i in range(5):
            lights[i] = source[i]
        line = Bitset(6)
        line.bits = list(map(int, format(n, '06b')))

        for i in range(5):
            res[i] = line
            for j in range(6):
                if line.test(j):
                    if j > 0:
                        lights[i].flip(j - 1)
                    if j < 5:
                        lights[i].flip(j + 1)
                    lights[i].flip(j)

            if i < 4:
                for j in range(6):
                    lights[i + 1].flip(j, line.test(j))
            line = lights[i]

        if lights[4].none():
            output(x)
            break

请注意，Python中没有内置的Bitset类，所以我创建了一个Bitset类来模拟C++中的bitset。此外，代码中的输入部分和输出部分也做了相应的修改以适应Python语法。