python连连看面向对象设计代码

Python连连看游戏的面向对象设计通常会将游戏中的元素抽象为类，包括但不限于方块（Block）、游戏区域（GameBoard）、操作者（Player）和游戏逻辑（Game）。以下是一个简单的Python连连看游戏的面向对象设计示例：

# 定义一个基础方块类
class Block:
    def __init__(self, value):
        self.value = value
        self.matched = False

# 方块可以设置匹配状态
class ConnectedBlock(Block):
    def match(self, other):
        if self.value == other.value:
            self.matched = other.matched = True

# 游戏区域类，包含方块列表
class GameBoard:
    def __init__(self, size):
        self.board = [[ConnectedBlock(i) for _ in range(size)] for _ in range(size)]
        
    # 检查相邻方块是否能匹配
    def check_matches(self, row, col):
        for dr, dc in [(0, 1), (0, -1), (1, 0), (-1, 0)]:
            new_row, new_col = row + dr, col + dc
            if 0 <= new_row < len(self.board) and 0 <= new_col < len(self.board) and not self.board[new_row][new_col].matched:
                self.board[row][col].match(self.board[new_row][new_col])

# 玩家类
class Player:
    def __init__(self, game_board):
        self.game_board = game_board
        self.move_history = []

    # 玩家点击方块进行匹配操作
    def click(self, row, col):
        self.move_history.append((row, col))
        self.game_board.check_matches(row, col)
        if all(block.matched for row in self.game_board.board for block in row):
            print("恭喜，游戏结束！")

# 示例游戏运行
def play_game():
    board = GameBoard(5)
    player = Player(board)
    # 进行游戏循环，玩家点击方块
    while not all(block.matched for row in board.board for block in row):
        row, col = input("请输入行和列（用逗号分隔）：").split(",")
        player.click(int(row), int(col))

play_game()