linux银行家算法实现c
时间: 2023-12-28 21:03:21 浏览: 90
银行家算法是一种避免死锁的算法,它通过动态地分配资源来避免进程死锁。下面是一个简单的Linux C语言实现:
```c
#include <stdio.h>
#include <stdbool.h>
#define P 5 // 进程数
#define R 3 // 资源数
int available[R] = {3, 3, 2}; // 可用资源
int max[P][R] = {{7, 5, 3}, {3, 2, 2}, {9, 0, 2}, {2, 2, 2}, {4, 3, 3}}; // 最大需求矩阵
int allocation[P][R] = {{0, 1, 0}, {2, 0, 0}, {3, 0, 2}, {2, 1, 1}, {0, 0, 2}}; // 已分配矩阵
int need[P][R]; // 需求矩阵
bool finish[P] = {false}; // 进程是否完成
void calculate_need() {
for (int i = 0; i < P; i++) {
for (int j = 0; j < R; j++) {
need[i][j] = max[i][j] - allocation[i][j];
}
}
}
bool is_safe() {
int work[R];
for (int i = 0; i < R; i++) {
work[i] = available[i];
}
bool finish_all = false;
while (!finish_all) {
bool can_allocate = false;
for (int i = 0; i < P; i++) {
if (!finish[i]) {
bool can_finish = true;
for (int j = 0; j < R; j++) {
if (need[i][j] > work[j]) {
can_finish = false;
break;
}
}
if (can_finish) {
can_allocate = true;
finish[i] = true;
for (int j = 0; j < R; j++) {
work[j] += allocation[i][j];
}
}
}
}
if (!can_allocate) {
for (int i = 0; i < P; i++) {
if (!finish[i]) {
return false;
}
}
finish_all = true;
}
}
return true;
}
bool request_resources(int pid, int request[]) {
for (int i = 0; i < R; i++) {
if (request[i] > need[pid][i] || request[i] > available[i]) {
return false;
}
}
for (int i = 0; i < R; i++) {
available[i] -= request[i];
allocation[pid][i] += request[i];
need[pid][i] -= request[i];
}
if (is_safe()) {
return true;
} else {
for (int i = 0; i < R; i++) {
available[i] += request[i];
allocation[pid][i] -= request[i];
need[pid][i] += request[i];
}
return false;
}
}
int main() {
calculate_need();
int pid = 1;
int request[R] = {0, 2, 0};
if (request_resources(pid, request)) {
printf("Request granted.\n");
} else {
printf("Request denied.\n");
}
return 0;
}
```
上述代码实现了银行家算法的主要逻辑,包括计算需求矩阵、判断是否安全、请求资源等。其中,`calculate_need()`函数用于计算需求矩阵,`is_safe()`函数用于判断当前状态是否安全,`request_resources()`函数用于请求资源并判断是否安全。在`main()`函数中,我们模拟了一个进程1请求2个资源的情况,并输出请求是否被允许。
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