对象json格式怎么转换/

以下是JS对象与JSON字符串之间的转换方法：
1.将JS对象转换为JSON字符串

let obj = {name: "John", age: 30, city: "New York"};
let jsonStr = JSON.stringify(obj);
console.log(jsonStr); // 输出：{"name":"John","age":30,"city":"New York"}

2.将JSON字符串转换为JS对象

let jsonStr = '{"name":"John","age":30,"city":"New York"}';
let obj = JSON.parse(jsonStr);
console.log(obj); // 输出：{name: "John", age: 30, city: "New York"}

3.将Java对象转换为JSON字符串

import com.alibaba.fastjson.JSON;
public class Test {
    public static void main(String[] args) {
        Person person = new Person("John", 30, "New York");
        String jsonStr = JSON.toJSONString(person);
        System.out.println(jsonStr); // 输出：{"age":30,"city":"New York","name":"John"}
    }
}
class Person {
    private String name;
    private int age;
    private String city;
    public Person(String name, int age, String city) {
        this.name = name;
        this.age = age;
        this.city = city;
    }
    // 省略getter和setter方法
}

4.将JSON字符串转换为Java对象

import com.alibaba.fastjson.JSON;
public class Test {
    public static void main(String[] args) {
        String jsonStr = "{\"age\":30,\"city\":\"New York\",\"name\":\"John\"}";
        Person person = JSON.parseObject(jsonStr, Person.class);
        System.out.println(person.getName()); // 输出：John
    }
}
class Person {
    private String name;
    private int age;
    private String city;
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public int getAge() {
        return age;
    }
    public void setAge(int age) {
        this.age = age;
    }
    public String getCity() {
        return city;
    }
    public void setCity(String city) {
        this.city = city;
    }
}