Given the following program class Game { private static final int DELAY = 500; private int x; public Game() { x = 0; } public void addX() { try { int y = x; Thread.sleep((int) (DELAY * Math.random())); y += 1; x = y; System.out.println("x=" + x); } catch (InterruptedException e) { } } } public class Homework8 { public static void main(String[] args) { var game = new Game(); for (int i = 0; i < 2; i++) { new Thread(() -> { for (int j = 0; j < 2; j++) game.addX(); }).start(); } } } The output could be x=1 x=1 x=2 x=2 or x=1 x=2 x=1 x=2 However, we desire the output to be x=1 x=2 x=3 x=4

To achieve the desired output `x=1 x=2 x=3 x=4`, we need to synchronize the `addX()` method to ensure that only one thread can access it at a time. We can use the `synchronized` keyword to achieve this.

Here is the modified `Game` class:

class Game {
    private static final int DELAY = 500;
    private int x;

    public Game() {
        x = 0;
    }

    public synchronized void addX() {
        try {
            int y = x;
            Thread.sleep((int) (DELAY * Math.random()));
            y += 1;
            x = y;
            System.out.println("x=" + x);
        } catch (InterruptedException e) {
        }
    }
}

In this modified `Game` class, the `addX()` method is synchronized using the `synchronized` keyword. This ensures that only one thread can execute the method at a time.

With this modification, the output of the program will always be `x=1 x=2 x=3 x=4`.