写出一个c语言编写的具有对局回放功能的五子棋小游戏

好的，以下是简单的五子棋小游戏的C语言代码，其中包含了对局回放功能：

#include <stdio.h>
#include <stdlib.h>

#define ROW 15
#define COL 15

char board[ROW][COL]; // 棋盘
char player1 = 'X'; // 玩家1执黑棋
char player2 = 'O'; // 玩家2执白棋

// 初始化棋盘
void init_board() {
    int i, j;
    for (i = 0; i < ROW; i++) {
        for (j = 0; j < COL; j++) {
            board[i][j] = '+';
        }
    }
}

// 打印棋盘
void print_board() {
    int i, j;
    printf("  ");
    for (i = 0; i < ROW; i++) {
        printf("%d ", i);
    }
    printf("\n");
    for (i = 0; i < ROW; i++) {
        printf("%d ", i);
        for (j = 0; j < COL; j++) {
            printf("%c ", board[i][j]);
        }
        printf("\n");
    }
}

// 判断是否有五子连珠
int check_win(char player) {
    int i, j, count;

    // 检查行
    for (i = 0; i < ROW; i++) {
        count = 0;
        for (j = 0; j < COL; j++) {
            if (board[i][j] == player) {
                count++;
            } else {
                count = 0;
            }
            if (count == 5) {
                return 1;
            }
        }
    }

    // 检查列
    for (j = 0; j < COL; j++) {
        count = 0;
        for (i = 0; i < ROW; i++) {
            if (board[i][j] == player) {
                count++;
            } else {
                count = 0;
            }
            if (count == 5) {
                return 1;
            }
        }
    }

    // 检查正斜线
    for (i = 0; i < ROW-4; i++) {
        for (j = 0; j < COL-4; j++) {
            count = 0;
            while (count < 5) {
                if (board[i+count][j+count] == player) {
                    count++;
                } else {
                    break;
                }
            }
            if (count == 5) {
                return 1;
            }
        }
    }

    // 检查反斜线
    for (i = 0; i < ROW-4; i++) {
        for (j = 4; j < COL; j++) {
            count = 0;
            while (count < 5) {
                if (board[i+count][j-count] == player) {
                    count++;
                } else {
                    break;
                }
            }
            if (count == 5) {
                return 1;
            }
        }
    }

    return 0;
}

// 玩家下棋
void player_move(char player) {
    int row, col;
    printf("玩家 %c 下棋：\n", player);
    printf("请输入行号和列号（用空格隔开）：");
    scanf("%d %d", &row, &col);
    while (board[row][col] != '+') {
        printf("这个位置已经有棋子了，请重新输入：");
        scanf("%d %d", &row, &col);
    }
    board[row][col] = player;
}

// 保存棋谱
void save_record(char player, int row, int col) {
    FILE *fp;
    fp = fopen("record.txt", "a");
    fprintf(fp, "%c %d %d\n", player, row, col);
    fclose(fp);
}

// 回放棋谱
void replay_game() {
    FILE *fp;
    char player;
    int row, col;
    fp = fopen("record.txt", "r");
    while (fscanf(fp, "%c %d %d\n", &player, &row, &col) != EOF) {
        board[row][col] = player;
        print_board();
    }
    fclose(fp);
}

int main() {
    int i, j, choice;
    char player = player1;

    init_board();
    print_board();

    while (!check_win(player1) && !check_win(player2)) {
        player_move(player);
        save_record(player, i, j);
        print_board();
        if (player == player1) {
            player = player2;
        } else {
            player = player1;
        }
    }

    printf("玩家 %c 获胜！\n", player);
    printf("是否回放对局？（1表示是，0表示否）：");
    scanf("%d", &choice);
    if (choice) {
        replay_game();
    }

    return 0;
}

在这个程序中，玩家可以通过输入行号和列号来下棋。每当一方下完棋后，程序会检查是否有五子连珠，如果有，则宣布胜利，并询问是否回放对局。如果选择回放对局，则程序会从记录文件中读取每一步棋的位置，并打印出棋盘。