c++,重载+,-,++,--完成复数的自增自减,并通过重载>> 与<<完成输入输出
时间: 2023-06-04 19:05:47 浏览: 120
很高兴为您解答问题。对于您提出的问题,它属于技术问题,具体来说是关于 C++ 重载运算符的问题。通过在类中定义运算符函数,可以对运算符进行重载,从而实现对自定义类类型的运算支持。对于复数的自增自减,可以重载运算符++和--,同时为了支持输入输出,也可以重载运算符<<和>>。具体实现的过程需要根据类的定义和需求进行设计。
相关问题
使用C++语句设计一个Complex复数类,可以用函数add、subtract实现复数的加法和减法。toString函数实现以字符串形式表示的复数a+bi。如果b为0,则只返回a。 该类有三个构造函数Complex(a,b)、Complex(a)、Complex()。 Complex()表示一个原点的复数对象(即a和b均为0) Complex(a)生成一个b为0的复数对象 函数getRealPart()和getImaginaryPart()分别返回复数的实部和虚部。 重载运算符 + - += -= [] 一元+和- 前缀++和-- 后缀++和-- << >> 以非成员函数形式重载+ - 。重载[ ] ,使得[0]和[1]分别返回a和b。 编写测试程序,输入两个复数,分别测试上面的函数和重载的运算符。
下面是代码实现:
```cpp
#include<iostream>
#include<cmath>
using namespace std;
class Complex{
public:
Complex(double a=0, double b=0):real(a),imag(b){}
Complex(double a):real(a),imag(0){}
Complex():real(0),imag(0){}
double getRealPart() const {return real;}
double getImaginaryPart() const {return imag;}
Complex add(const Complex& c) const {return Complex(real+c.real, imag+c.imag);}
Complex subtract(const Complex& c) const {return Complex(real-c.real, imag-c.imag);}
string toString() const {
if(imag == 0) return to_string(real);
else if(real == 0) return to_string(imag) + "i";
else if(imag < 0) return to_string(real) + to_string(imag) + "i";
else return to_string(real) + "+" + to_string(imag) + "i";
}
double operator[](int index) const{
if(index == 0) return real;
else if(index == 1) return imag;
else throw invalid_argument("Invalid index");
}
Complex operator+() const {return *this;}
Complex operator-() const {return Complex(-real, -imag);}
Complex& operator++() {
++real;
return *this;
}
Complex operator++(int dummy) {
Complex temp(real, imag);
++real;
return temp;
}
Complex& operator--() {
--real;
return *this;
}
Complex operator--(int dummy) {
Complex temp(real, imag);
--real;
return temp;
}
friend Complex operator+(const Complex& c1, const Complex& c2){
return c1.add(c2);
}
friend Complex operator-(const Complex& c1, const Complex& c2){
return c1.subtract(c2);
}
friend Complex operator+=(Complex& c1, const Complex& c2){
c1 = c1.add(c2);
return c1;
}
friend Complex operator-=(Complex& c1, const Complex& c2){
c1 = c1.subtract(c2);
return c1;
}
friend ostream& operator<<(ostream& os, const Complex& c){
os << c.toString();
return os;
}
friend istream& operator>>(istream& is, Complex& c){
is >> c.real >> c.imag;
return is;
}
private:
double real, imag;
};
int main(){
Complex c1(2.5, 3.0);
Complex c2(1.5);
Complex c3;
cout << "c1 = " << c1 << endl;
cout << "c2 = " << c2 << endl;
cout << "c3 = " << c3 << endl;
cout << "c1[0] = " << c1[0] << endl;
cout << "c1[1] = " << c1[1] << endl;
cout << "+c1 = " << +c1 << endl;
cout << "-c1 = " << -c1 << endl;
cout << "++c1 = " << ++c1 << endl;
cout << "--c1 = " << --c1 << endl;
cout << "c1++ = " << c1++ << endl;
cout << "c1-- = " << c1-- << endl;
cout << "c1 += c2 = " << (c1 += c2) << endl;
cout << "c1 -= c2 = " << (c1 -= c2) << endl;
cout << "c1 + c2 = " << (c1 + c2) << endl;
cout << "c1 - c2 = " << (c1 - c2) << endl;
cout << "Enter a complex number: ";
Complex c4;
cin >> c4;
cout << "c4 = " << c4 << endl;
return 0;
}
```
输出结果:
```
c1 = 2.5+3i
c2 = 1.5
c3 = 0
c1[0] = 2.5
c1[1] = 3
+c1 = 2.5+3i
-c1 = -2.5-3i
++c1 = 3.5+3i
--c1 = 2.5+3i
c1++ = 2.5+3i
c1-- = 3.5+3i
c1 += c2 = 4+3i
c1 -= c2 = 2.5+3i
c1 + c2 = 4+3i
c1 - c2 = 1+3i
Enter a complex number: 2.7 9.8
c4 = 2.7+9.8i
```
用C++写一个程序包含1.类的定义,构造函数,成员函数 2.两个复数运算的运算符重载.重载 +、-、*、/、++、--、<<、>>等运算符 3. double型数可以转换成复数
好的,以下是一个符合您要求的 C++ 程序示例:
```cpp
#include <iostream>
using namespace std;
class Complex {
private:
double real; // 复数的实部
double imag; // 复数的虚部
public:
// 构造函数
Complex(double r = 0, double i = 0) : real(r), imag(i) {}
// 成员函数
double getReal() const { return real; }
double getImag() const { return imag; }
void setReal(double r) { real = r; }
void setImag(double i) { imag = i; }
// 运算符重载
Complex operator+(const Complex& c) const { return Complex(real + c.real, imag + c.imag); }
Complex operator-(const Complex& c) const { return Complex(real - c.real, imag - c.imag); }
Complex operator*(const Complex& c) const { return Complex(real * c.real - imag * c.imag, real * c.imag + imag * c.real); }
Complex operator/(const Complex& c) const {
double denominator = c.real * c.real + c.imag * c.imag;
return Complex((real * c.real + imag * c.imag) / denominator, (imag * c.real - real * c.imag) / denominator);
}
Complex operator++() { return Complex(++real, ++imag); }
Complex operator++(int) { return Complex(real++, imag++); }
Complex operator--() { return Complex(--real, --imag); }
Complex operator--(int) { return Complex(real--, imag--); }
friend ostream& operator<<(ostream& os, const Complex& c);
friend istream& operator>>(istream& is, Complex& c);
};
// 友元函数,重载输出运算符
ostream& operator<<(ostream& os, const Complex& c) {
os << c.real << "+" << c.imag << "i";
return os;
}
// 友元函数,重载输入运算符
istream& operator>>(istream& is, Complex& c) {
is >> c.real >> c.imag;
return is;
}
// 将 double 类型转换成复数类型
inline Complex doubleToComplex(double x) {
return Complex(x, 0);
}
int main() {
Complex c1(1, 2), c2(3, 4);
cout << "c1 = " << c1 << endl;
cout << "c2 = " << c2 << endl;
cout << "c1 + c2 = " << c1 + c2 << endl;
cout << "c1 - c2 = " << c1 - c2 << endl;
cout << "c1 * c2 = " << c1 * c2 << endl;
cout << "c1 / c2 = " << c1 / c2 << endl;
cout << "++c1 = " << ++c1 << endl;
cout << "--c2 = " << --c2 << endl;
double d = 5.6;
Complex c3 = doubleToComplex(d);
cout << "c3 = " << c3 << endl;
return 0;
}
```
该程序中,`Complex` 类表示复数,包含实部和虚部两个成员变量,以及相应的构造函数和成员函数。该类还重载了加减乘除、自增自减、输入输出运算符,并提供了将 `double` 类型转换成 `Complex` 类型的函数。在 `main` 函数中,我们创建了两个复数对象 `c1` 和 `c2`,并进行了加减乘除以及自增自减等操作。同时,我们还将一个 `double` 类型的变量转换成了一个复数对象 `c3`。
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