c++,重载+,-,++,--完成复数的自增自减,并通过重载>> 与<<完成输入输出
时间: 2023-06-04 11:05:47 浏览: 77
很高兴为您解答问题。对于您提出的问题,它属于技术问题,具体来说是关于 C++ 重载运算符的问题。通过在类中定义运算符函数,可以对运算符进行重载,从而实现对自定义类类型的运算支持。对于复数的自增自减,可以重载运算符++和--,同时为了支持输入输出,也可以重载运算符<<和>>。具体实现的过程需要根据类的定义和需求进行设计。
相关问题
c➕➕实现运算符重载+,-,重载<<,>>,通过对象进行输出运算后结果。
好的,我可以为您解答。首先,运算符重载是 C++ 中非常重要的概念之一,它允许我们重载现有的运算符,以便我们可以对我们自己定义的类型执行特定的操作。在本例中,我们需要重载+和-运算符以实现加法和减法,同时需要重载<<和>>运算符以实现输入和输出。
下面是一个示例代码,可以帮助您更好地理解:
```c++
#include <iostream>
using namespace std;
class Complex {
private:
int real;
int imag;
public:
Complex(int r = 0, int i = 0) {
real = r;
imag = i;
}
Complex operator+(Complex const &obj) {
Complex res;
res.real = real + obj.real;
res.imag = imag + obj.imag;
return res;
}
Complex operator-(Complex const &obj) {
Complex res;
res.real = real - obj.real;
res.imag = imag - obj.imag;
return res;
}
friend ostream &operator<<(ostream &out, const Complex &c);
friend istream &operator>>(istream &in, Complex &c);
};
ostream &operator<<(ostream &out, const Complex &c) {
out << c.real;
out << "+i" << c.imag << endl;
return out;
}
istream &operator>>(istream &in, Complex &c) {
cout << "Enter Real Part: ";
in >> c.real;
cout << "Enter Imaginary Part: ";
in >> c.imag;
return in;
}
int main() {
Complex c1, c2;
cout << "Enter first complex number:\n";
cin >> c1;
cout << "Enter second complex number:\n";
cin >> c2;
Complex c3 = c1 + c2;
Complex c4 = c1 - c2;
cout << "First Complex Number: " << c1;
cout << "Second Complex Number: " << c2;
cout << "Sum of Two Complex Numbers: " << c3;
cout << "Difference of Two Complex Numbers: " << c4;
return 0;
}
```
在上面的代码中,我们定义了一个名为Complex的类,其中包括两个私有变量real和imag,表示实部和虚部。我们还定义了两个运算符重载函数,分别用于实现加法和减法。在重载运算符函数中,我们使用“+”和“-”运算符来执行实际的加法和减法操作,并返回结果。此外,我们还定义了两个友元函数,用于重载输入和输出运算符。在这些函数中,我们使用“<<”和“>>”运算符来执行输入和输出操作。
最后,在主函数中,我们创建了两个复数对象c1和c2,并使用cin输入它们的值。然后,我们使用重载的加法和减法运算符计算它们的和和差,并将结果存储在c3和c4中。最后,我们使用重载的输出运算符将所有复数对象的值打印到屏幕上。
希望这个例子可以帮助您更好地理解C++运算符重载的概念。
用c++为复数类Complex重载实现+,-,*,/,<<,>>等运算符
好的,下面是一个简单的复数类Complex,重载了+,-,*,/,<<,>>等运算符的示例代码:
```c++
#include <iostream>
using namespace std;
class Complex {
public:
Complex(double real = 0, double imag = 0) : m_real(real), m_imag(imag) {}
Complex(const Complex& other) : m_real(other.m_real), m_imag(other.m_imag) {}
Complex operator+(const Complex& other) const {
return Complex(m_real + other.m_real, m_imag + other.m_imag);
}
Complex operator-(const Complex& other) const {
return Complex(m_real - other.m_real, m_imag - other.m_imag);
}
Complex operator*(const Complex& other) const {
return Complex(m_real * other.m_real - m_imag * other.m_imag, m_real * other.m_imag + m_imag * other.m_real);
}
Complex operator/(const Complex& other) const {
double denominator = other.m_real * other.m_real + other.m_imag * other.m_imag;
return Complex((m_real * other.m_real + m_imag * other.m_imag) / denominator, (m_imag * other.m_real - m_real * other.m_imag) / denominator);
}
friend ostream& operator<<(ostream& os, const Complex& c) {
os << "(" << c.m_real << ", " << c.m_imag << ")";
return os;
}
friend istream& operator>>(istream& is, Complex& c) {
is >> c.m_real >> c.m_imag;
return is;
}
private:
double m_real;
double m_imag;
};
int main() {
Complex c1(1, 2);
Complex c2(3, 4);
cout << "c1 = " << c1 << endl;
cout << "c2 = " << c2 << endl;
cout << "c1 + c2 = " << c1 + c2 << endl;
cout << "c1 - c2 = " << c1 - c2 << endl;
cout << "c1 * c2 = " << c1 * c2 << endl;
cout << "c1 / c2 = " << c1 / c2 << endl;
Complex c3;
cout << "Input a complex number: ";
cin >> c3;
cout << "The complex number you input is: " << c3 << endl;
return 0;
}
```
在上述代码中,我们重载了Complex类的+,-,*,/,<<,>>等运算符,并利用了友元函数的特性来重载输出运算符<<和输入运算符>>。在main函数中,我们对重载后的运算符进行了测试,输出了两个复数的和、差、积、商以及用户输入的复数。
希望这个示例代码对你有所帮助。