def solve_tag(answer,sentence): result = [] hidden_state = ["B", "M", "E", "S"] for i in range(len(answer)): if(hidden_state[int(answer[i])]=='E' or hidden_state[int(answer[i])]=='S'): result.append(sentence[i]) result.append(" ") else: result.append(sentence[i]) return result解释以上代码
时间: 2024-04-26 09:24:30 浏览: 14
这段代码是一个函数,名为 `solve_tag`,它接受两个参数:一个是标注(即分好词的句子的词性标注),另一个是句子本身。这个函数的作用是将标注后的句子转换成原始的句子。
函数首先定义了一个列表 `hidden_state`,里面存储了四个元素:`"B"`、`"M"`、`"E"` 和 `"S"`,它们代表了中文分词中的四种词性。接下来,函数遍历了标注后的句子中的每个字符,判断其对应的词性是否为 `"E"` 或 `"S"`。如果是,说明当前字符是一个词的结尾,需要在结果列表 `result` 中增加一个空格;否则说明当前字符还不是词的结尾,直接将其添加到结果列表中。最后,函数返回结果列表 `result`,其中每个词之间用空格隔开。
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给下面代码加上注释import numpy as np import pickle def solve_tag(answer,sentence): result = [] hidden_state = ["B", "M", "E", "S"] for i in range(len(answer)): if(hidden_state[int(answer[i])]=='E' or hidden_state[int(answer[i])]=='S'): result.append(sentence[i]) result.append(" ") else: result.append(sentence[i]) return result
# 导入 numpy 和 pickle 库
import numpy as np
import pickle
def solve_tag(answer,sentence):
# 定义隐藏状态列表
hidden_state = ["B", "M", "E", "S"]
# 初始化结果列表
result = []
# 循环遍历答案列表
for i in range(len(answer)):
# 判断当前标记是否为"E"或"S"
if(hidden_state[int(answer[i])]=='E' or hidden_state[int(answer[i])]=='S'):
# 将当前字符添加到结果列表中
result.append(sentence[i])
# 添加空格
result.append(" ")
else:
# 将当前字符添加到结果列表中
result.append(sentence[i])
# 返回结果列表
return result
import collections def solve_method(n: int) -> None: asc = True list_ = collections.deque() x = 1 for i in range(1, n + 1): arr = [0] * i if asc: for j in range(i): arr[j] = x x += 1 else: for j in range(i - 1, -1, -1): arr[j] = x x += 1 list_.appendleft(arr) asc = not asc res = [] head = "" for ints in list_: content = head for j in range(len(ints)): num = ints[j] content += str(num) content += "*" * (4 - len(str(num))) if j != len(ints) - 1: content += " " res.append(content) head += " " for s in reversed(res): print(s) if __name__ == "__main__": n = int(input()) solve_method(n) 改写以上代码,python
import collections
def solve_method(n):
asc = True
list_ = collections.deque()
x = 1
for i in range(1, n + 1):
arr = [0] * i
if asc:
for j in range(i):
arr[j] = x
x += 1
else:
for j in range(i - 1, -1, -1):
arr[j] = x
x += 1
list_.appendleft(arr)
asc = not asc
res = []
head = ""
for ints in list_:
content = head
for j in range(len(ints)):
num = ints[j]
content += str(num)
content += "*" * (4 - len(str(num)))
if j != len(ints) - 1:
content += " "
res.append(content)
head += " "
for s in reversed(res):
print(s)
if __name__ == "__main__":
n = int(input())
solve_method(n)