python贪吃蛇代码实现

下面是一个简单的Python贪吃蛇游戏的代码实现：

import pygame
import random

# 初始化游戏
pygame.init()

# 定义颜色
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
GREEN = (0, 255, 0)
RED = (255, 0, 0)

# 设置屏幕尺寸
screen_width = 640
screen_height = 480
screen = pygame.display.set_mode((screen_width, screen_height))
pygame.display.set_caption("贪吃蛇游戏")

# 定义蛇的初始位置和速度
snake_pos = [[100, 50], [90, 50], [80, 50]]
snake_speed = [10, 0]

# 定义食物的初始位置
food_pos = [random.randrange(1, (screen_width//10)) * 10,
            random.randrange(1, (screen_height//10)) * 10]
food_spawn = True

# 初始化计分
score = 0

# 游戏主循环
game_over = False
clock = pygame.time.Clock()

while not game_over:
    # 处理事件
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            game_over = True

    # 检测按键操作
    keys = pygame.key.get_pressed()
    for key in keys:
        if keys[pygame.K_LEFT]:
            snake_speed = [-10, 0]
        if keys[pygame.K_RIGHT]:
            snake_speed = [10, 0]
        if keys[pygame.K_UP]:
            snake_speed = [0, -10]
        if keys[pygame.K_DOWN]:
            snake_speed = [0, 10]

    # 移动蛇的头部
    snake_pos[0][0] += snake_speed[0]
    snake_pos[0][1] += snake_speed[1]

    # 检测蛇与食物的碰撞
    if snake_pos[0][0] == food_pos[0] and snake_pos[0][1] == food_pos[1]:
        score += 1
        food_spawn = False
    else:
        snake_pos.pop()

    # 重新生成食物
    if not food_spawn:
        food_pos = [random.randrange(1, (screen_width // 10)) * 10,
                    random.randrange(1, (screen_height // 10)) * 10]
    food_spawn = True

    # 绘制屏幕
    screen.fill(BLACK)
    for pos in snake_pos:
        pygame.draw.rect(screen, GREEN, pygame.Rect(
            pos[0], pos[1], 10, 10))

    pygame.draw.rect(screen, RED, pygame.Rect(
        food_pos[0], food_pos[1], 10, 10))

    # 游戏结束判断
    if snake_pos[0][0] < 0 or snake_pos[0][0] > screen_width-10:
        game_over = True
    if snake_pos[0][1] < 0 or snake_pos[0][1] > screen_height-10:
        game_over = True

    for block in snake_pos[1:]:
        if snake_pos[0][0] == block[0] and snake_pos[0][1] == block[1]:
            game_over = True

    pygame.display.update()

    # 控制游戏速度
    clock.tick(30)

# 退出游戏
pygame.quit()

以上就是一个简单的Python贪吃蛇游戏的代码实现。你可以将代码复制到Python环境中运行，即可开始游戏。祝你玩得开心！