用C++写一个学生信息管理系统程序

好的，我可以回答这个问题。以下是一个简单的学生信息管理系统的 C 代码：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define MAX_SIZE 100

struct Student {
    char name[20];
    int id;
    float grade;
};

int main() {
    struct Student students[MAX_SIZE];
    int n = 0;

    while (1) {
        int option;
        printf("\n1. Add student\n2. Remove student\n3. Show all students\n4. Exit\n");
        printf("Enter option: ");
        scanf("%d", &option);

        switch(option) {
            case 1: {
                struct Student student;
                printf("Enter name: ");
                scanf("%s", student.name);
                printf("Enter id: ");
                scanf("%d", &student.id);
                printf("Enter grade: ");
                scanf("%f", &student.grade);

                students[n] = student;
                n++;
                printf("Added student successfully.\n");
                break;
            }

            case 2: {
                int id;
                printf("Enter id of student to remove: ");
                scanf("%d", &id);

                int found = 0;
                for (int i = 0; i < n; i++) {
                    if (students[i].id == id) {
                        found = 1;
                        for (int j = i; j < n - 1; j++) {
                            students[j] = students[j+1];
                        }
                        n--;
                        printf("Removed student successfully.\n");
                        break;
                    }
                }
                if (!found) {
                    printf("Student with id %d not found.\n", id);
                }
                break;
            }

            case 3: {
                printf("Name\tID\tGrade\n");
                for (int i = 0; i < n; i++) {
                    printf("%s\t%d\t%.2f\n", students[i].name, students[i].id, students[i].grade);
                }
                break;
            }

            case 4: {
                printf("Exiting program...\n");
                exit(0);
            }

            default: {
                printf("Invalid option, please try again.\n");
                break;
            }
        }
    }

    return 0;
}

请注意，这只是一个非常简单的示例程序，可能需要进一步的测试和开发才能满足真正的需求。