c语言触摸屏登陆界面代码
时间: 2023-06-23 20:53:03 浏览: 154
登陆界面的代码
以下是一个基本的 C 语言触摸屏登陆界面的示例代码,您可以根据具体的需求进行自定义和扩展:
```c
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <termios.h>
#include <fcntl.h>
#include <unistd.h>
#define USERNAME "admin"
#define PASSWORD "123456"
int getch(void)
{
struct termios tm, tm_old;
int fd = STDIN_FILENO, c;
if (tcgetattr(fd, &tm) < 0) return -1;
tm_old = tm;
cfmakeraw(&tm);
if (tcsetattr(fd, TCSANOW, &tm) < 0) return -1;
c = getchar();
if (tcsetattr(fd, TCSANOW, &tm_old) < 0) return -1;
return c;
}
int main()
{
int fd;
char buf[16], *p;
int n = 0;
fd = open("/dev/input/event0", O_RDONLY);
if (fd < 0) {
perror("open");
exit(1);
}
printf("Please enter your username and password:\n");
printf("Username: ");
while (1) {
char ch = getch();
if (ch == '\r' || ch == '\n') {
buf[n] = '\0';
break;
} else if (ch == 127 || ch == '\b') {
if (n > 0) {
n--;
printf("\b \b");
}
} else if (n < 15) {
buf[n] = ch;
n++;
printf("*");
}
}
printf("\nPassword: ");
n = 0;
while (1) {
char ch = getch();
if (ch == '\r' || ch == '\n') {
buf[n] = '\0';
break;
} else if (ch == 127 || ch == '\b') {
if (n > 0) {
n--;
printf("\b \b");
}
} else if (n < 15) {
buf[n] = ch;
n++;
printf("*");
}
}
printf("\n");
if (strcmp(buf, USERNAME) == 0 && strcmp(buf + strlen(USERNAME) + 1, PASSWORD) == 0) {
printf("Login successful!\n");
} else {
printf("Login failed!\n");
}
close(fd);
return 0;
}
```
该示例代码通过读取 Linux 系统下的触摸屏设备文件 `/dev/input/event0`,实现了一个简单的用户名和密码登陆界面。您可以根据自己的实际需求,进行修改和扩展。
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