Напиши игру тетрис на python

当然，我可以为您提供一个简单的示例来编写Python的俄罗斯方块游戏（Tetris）。以下是一个基本的实现示例：

import pygame
import random

# 游戏窗口大小
WINDOW_WIDTH = 800
WINDOW_HEIGHT = 600

# 方块大小
BLOCK_SIZE = 30

# 方块颜色
COLORS = [
    (0, 0, 0),
    (255, 0, 0),
    (0, 255, 0),
    (0, 0, 255),
    (255, 255, 0),
    (255, 0, 255),
    (0, 255, 255),
    (128, 128, 128)
]

# 方块形状
SHAPES = [
    [[1, 1, 1, 1]],
    [[1, 1], [1, 1]],
    [[1, 1, 0], [0, 1, 1]],
    [[0, 1, 1], [1, 1, 0]],
    [[1, 1, 1], [0, 1, 0]],
    [[1, 1, 1], [1, 0, 0]],
    [[1, 1, 1], [0, 0, 1]]
]

def draw_block(surface, x, y, color):
    pygame.draw.rect(surface, color, (x * BLOCK_SIZE, y * BLOCK_SIZE, BLOCK_SIZE, BLOCK_SIZE))

def draw_board(surface, board):
    for y in range(len(board)):
        for x in range(len(board[y])):
            draw_block(surface, x, y, COLORS[board[y][x]])

def check_collision(board, shape, x, y):
    for row in range(len(shape)):
        for col in range(len(shape[row])):
            if shape[row][col] and (x + col >= len(board) or x + col < 0 or y + row >= len(board) or board[y + row][x + col]):
                return True
    return False

def rotate_shape(shape):
    return list(zip(*reversed(shape)))

def clear_rows(board):
    full_rows = [row for row in range(len(board)) if all(board[row])]
    for row in full_rows:
        del board[row]
        board.insert(0,  * len(board))
    return len(full_rows)

def main():
    pygame.init()
    screen = pygame.display.set_mode((WINDOW_WIDTH, WINDOW_HEIGHT))
    pygame.display.set_caption("Tetris")

    clock = pygame.time.Clock()

    board = [ * (WINDOW_WIDTH // BLOCK_SIZE) for _ in range(WINDOW_HEIGHT // BLOCK_SIZE)]
    current_shape = random.choice(SHAPES)
    current_x = WINDOW_WIDTH // BLOCK_SIZE // 2 - len(current_shape) // 2
    current_y = 0

    score = 0

    game_over = False

    while not game_over:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                game_over = True
            elif event.type == pygame.KEYDOWN:
                if event.key == pygame.K_LEFT:
                    if not check_collision(board, current_shape, current_x - 1, current_y):
                        current_x -= 1
                elif event.key == pygame.K_RIGHT:
                    if not check_collision(board, current_shape, current_x + 1, current_y):
                        current_x += 1
                elif event.key == pygame.K_DOWN:
                    if not check_collision(board, current_shape, current_x, current_y + 1):
                        current_y += 1
                elif event.key == pygame.K_UP:
                    rotated_shape = rotate_shape(current_shape)
                    if not check_collision(board, rotated_shape, current_x, current_y):
                        current_shape = rotated_shape

        if not check_collision(board, current_shape, current_x, current_y + 1):
            current_y += 1
        else:
            for row in range(len(current_shape)):
                for col in range(len(current_shape[row])):
                    if current_shape[row][col]:
                        board[current_y + row][current_x + col] = len(COLORS) - 1
            score += clear_rows(board)
            current_shape = random.choice(SHAPES)
            current_x = WINDOW_WIDTH // BLOCK_SIZE // 2 - len(current_shape) // 2
            current_y = 0
            if check_collision(board, current_shape, current_x, current_y):
                game_over = True

        screen.fill((255, 255, 255))
        draw_board(screen, board)
        for row in range(len(current_shape)):
            for col in range(len(current_shape[row])):
                if current_shape[row][col]:
                    draw_block(screen, current_x + col, current_y + row, COLORS[len(COLORS) - 1])
        pygame.display.flip()
        clock.tick(5)

    pygame.quit()

if __name__ == "__main__":
    main()

这是一个简单的俄罗斯方块游戏的实现，使用了Pygame库来进行图形界面的绘制和交互。您可以在Python环境中运行此代码，即可开始游戏。