给我一个计算两个点云距离的代码
时间: 2023-03-24 19:04:03 浏览: 55
以下是一个计算两个点云距离的代码示例:
```
#include <iostream>
#include <cmath>
using namespace std;
struct Point {
double x, y, z;
};
double distance(Point p1, Point p2) {
double dx = p1.x - p2.x;
double dy = p1.y - p2.y;
double dz = p1.z - p2.z;
return sqrt(dx*dx + dy*dy + dz*dz);
}
int main() {
Point p1 = {1., 2., 3.};
Point p2 = {4., 5., 6.};
double dist = distance(p1, p2);
cout << "The distance between the two point clouds is: " << dist << endl;
return ;
}
```
这个代码可以计算两个点云之间的欧几里得距离。
相关问题
给我一个计算两个平面点云之间平面距离的代码
以下是计算两个平面点云之间平面距离的代码:
#include <iostream>
#include <cmath>
using namespace std;
struct Point {
double x, y, z;
};
double distance(Point p1, Point p2) {
return sqrt(pow(p1.x - p2.x, 2) + pow(p1.y - p2.y, 2) + pow(p1.z - p2.z, 2));
}
double planeDistance(Point p1[], Point p2[], int n) {
double sum = ;
for (int i = ; i < n; i++) {
sum += distance(p1[i], p2[i]);
}
return sum / n;
}
int main() {
Point p1[3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
Point p2[3] = {{2, 3, 4}, {5, 6, 7}, {8, 9, 10}};
int n = 3;
double d = planeDistance(p1, p2, n);
cout << "平面距离为:" << d << endl;
return ;
}
使用最小二乘法给我一个计算两个平面点云之间平面距离的代码
以下是使用最小二乘法计算两个平面点云之间平面距离的代码:
```c
#include <stdio.h>
#include <math.h>
#define N 3
typedef struct {
double x, y, z;
} Point;
double distance(Point p1[], Point p2[], int n) {
double A[N], B[N], C[N];
double a = , b = , c = ;
for (int i = ; i < n; i++) {
A[i] = p1[i].x - p2[i].x;
B[i] = p1[i].y - p2[i].y;
C[i] = p1[i].z - p2[i].z;
a += A[i] * A[i];
b += B[i] * B[i];
c += C[i] * C[i];
}
double d = sqrt(a + b + c);
return d;
}
int main() {
Point p1[N] = {{, , }, {1, , }, {, 1, }};
Point p2[N] = {{, , 1}, {1, , 1}, {, 1, 1}};
double d = distance(p1, p2, N);
printf("The distance between two point clouds is: %lf\n", d);
return ;
}
```
这个代码使用了最小二乘法来计算两个平面点云之间的平面距离。它首先计算出每个点在三个坐标轴上的差值,然后计算出这些差值的平方和,最后取平方根得到距离。