输入几个数字，找到众数，若众数存在且唯一，则输出众数;若众数存在但不唯一，则输出众数的平均数:若众数不存在，则输出所有输入数字的平均值的代码

以下是代码：

#include <stdio.h>

int main() {
int n, i, j, count, maxCount = , mode = , sum = , numCount = ;
float avg;

printf("请输入数字个数：");
scanf("%d", &n);

int nums[n];

printf("请输入数字：");
for (i = ; i < n; i++) {
scanf("%d", &nums[i]);
sum += nums[i];
}

avg = (float)sum / n;

for (i = ; i < n; i++) {
count = ;
for (j = ; j < n; j++) {
if (nums[j] == nums[i]) {
count++;
}
}
if (count > maxCount) {
maxCount = count;
mode = nums[i];
}
}

for (i = ; i < n; i++) {
if (nums[i] == mode) {
numCount++;
}
}

if (maxCount == 1) {
printf("众数为：%d\n", mode);
} else if (maxCount > 1) {
printf("众数的平均数为：%.2f\n", (float)(mode * numCount) / maxCount);
} else {
printf("所有输入数字的平均值为：%.2f\n", avg);
}

return ;
}