C#实现从yaml文件中获取某个根节点buildReleases下父节点buildEnvironments的子结点buildSystem的节点值

在C#中，你可以使用`YAML.NET`库来解析YAML文件并获取特定节点的值。首先，需要安装`YAMLDotNet`库。下面是一个示例，展示如何从给定的YAML字符串中获取指定路径的值：

using System;
using YAML Ain't markup language;
using YAMLDotNet.Serialization;

public class BuildNode
{
    public string buildReleases { get; set; }
    public BuildEnvironmentNode buildEnvironments { get; set; }
    public BuildSystemNode buildSystem { get; set; }
}

public class BuildEnvironmentNode
{
    public BuildSystemNode buildSystem { get; set; }
    // 其他属性...
}

public class BuildSystemNode
{
    public string value { get; set; } // 这里假设value是你想要的键值
}

public static string GetValueFromYaml(string yamlContent, string path)
{
    var deserializer = new DeserializerBuilder().Build();
    BuildNode root = null;
    try
    {
        root = deserializer.Deserialize<BuildNode>(yamlContent);
    }
    catch (YamlException e)
    {
        throw new ArgumentException("Invalid YAML content", e);
    }

    string result = "";
    var parts = path.Split('.');
    foreach (string part in parts)
    {
        if (root != null && root.GetType().GetProperty(part) != null)
        {
            root = (BuildNode)(root.GetType().GetProperty(part).GetValue(root));
        }
        else
        {
            result = "Path not found";
            break;
        }
    }

    if (root != null && root.buildSystem != null && root.buildSystem.value != null)
    {
        result = root.buildSystem.value;
    }

    return result;
}

在这个例子中，`path`应该是类似"buildReleases.buildEnvironments.buildSystem.value"的形式，表示你想要获取的完整路径。