for (x=a;x>0;x=x/10){ y=x%10; num = num*10+y;
时间: 2024-06-01 11:10:26 浏览: 22
if (y==0) {num = num+5;} else if (y==5) {num = num+0;} else if (y==6) {num = num+1;} else if (y==7) {num = num+2;} else if (y==8) {num = num+3;} else if (y==9) {num = num+4;} } return num;}
This code takes in an integer value 'a' and converts it into a new integer value 'num' by iterating through each digit of 'a' and applying a specific transformation to it.
The 'for' loop iterates through each digit of 'a' by dividing 'a' by 10 each time and updating the value of 'x'.
The line 'y=x%' extracts the last digit of 'x' and assigns it to the variable 'y'.
The if-else statements that follow apply a specific transformation to 'y' depending on its value, and then add the transformed value to 'num'.
Finally, the function returns the new integer value 'num'.