python The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

In Python, when you try to evaluate the truth value of an array with more than one element, it can be ambiguous because it is not clear which element or elements you are referring to. To resolve this ambiguity, you can use either the `any()` or `all()` function.

The `any()` function returns `True` if at least one element in the array is true, and `False` otherwise. The `all()` function, on the other hand, returns `True` only if all elements in the array are true; otherwise, it returns `False`.

Here's an example to illustrate their usage:

import numpy as np

arr = np.array([True, False, True])

# Using any()
if arr.any():
    print("At least one element is true")
else:
    print("No element is true")

# Using all()
if arr.all():
    print("All elements are true")
else:
    print("Not all elements are true")

In this example, since there is at least one `True` value in the array, the output will be:

At least one element is true
Not all elements are true