linux进行石头剪刀布三局两胜

在Linux环境中，你可以编写一个简单的交互式shell脚本来实现石头剪刀布游戏的"三局两胜"规则。这通常涉及到用户输入、随机选择电脑选项以及判断胜负的过程。以下是一个基本的示例：

#!/bin/bash

# 定义游戏选项
options=("rock" "paper" "scissors")

# 游戏函数
play() {
  # 用户输入
  read -p "Please choose rock, paper, or scissors: " user_choice
  # 随机电脑选择
  computer_choice=$(shuf -e "${options[@]}")
  echo "Computer chose: $computer_choice"

  # 判断输赢
  if [ "$user_choice" == "$computer_choice" ]; then
    echo "It's a tie!"
  elif [ $(echo "$user_choice > $computer_choice" | bc) -eq 1 ]; then
    echo "You win this round!"
  else
    echo "Computer wins this round!"
  fi
}

# 三局两胜循环
for ((i = 0; i < 3; i++)); do
  play
  if [[ $? -eq 0 && $i == 1 ]]; then
    echo "You've won two out of three rounds! You win the game!"
    break
  elif [[ $? -eq 0 && $i == 2 ]]; then
    echo "You lost two out of three rounds! Computer wins the game!"
    break
  fi
done