用python写个单链表且用头插法将一个列表a=[11,22,33,44,55]建一个表
时间: 2023-05-30 14:04:04 浏览: 44
```python
class Node:
def __init__(self, data=None):
self.data = data
self.next = None
class LinkedList:
def __init__(self):
self.head = None
def add_at_beginning(self, data):
new_node = Node(data)
new_node.next = self.head
self.head = new_node
def print_list(self):
current_node = self.head
while current_node:
print(current_node.data)
current_node = current_node.next
a = [11, 22, 33, 44, 55]
linked_list = LinkedList()
for i in a:
linked_list.add_at_beginning(i)
linked_list.print_list()
```
输出:
```
55
44
33
22
11
```