帮我用python做一个150行代码的贪吃蛇小游戏
时间: 2023-08-28 19:35:57 浏览: 39
好的,我可以帮你实现一个简单的贪吃蛇小游戏,但需要提醒的是,150行代码可能不够完整和优化,仅供参考。以下是代码实现:
```python
import pygame
import random
# 初始化 pygame
pygame.init()
# 定义游戏界面大小
width = 800
height = 600
# 定义颜色
white = (255, 255, 255)
black = (0, 0, 0)
red = (255, 0, 0)
green = (0, 255, 0)
blue = (0, 0, 255)
gray = (128, 128, 128)
# 创建游戏界面
screen = pygame.display.set_mode((width, height))
pygame.display.set_caption("贪吃蛇小游戏")
# 定义字体
font = pygame.font.SysFont(None, 30)
# 定义蛇的初始位置和大小
snake_size = 10
snake_x = width / 2
snake_y = height / 2
# 定义蛇的移动速度
snake_speed = 10
# 定义蛇的初始移动方向
direction = "right"
# 定义食物的初始位置
food_x = round(random.randrange(0, width - snake_size) / 10.0) * 10.0
food_y = round(random.randrange(0, height - snake_size) / 10.0) * 10.0
# 定义分数
score = 0
# 绘制蛇的函数
def draw_snake(snake_size, snake_list):
for x, y in snake_list:
pygame.draw.rect(screen, green, [x, y, snake_size, snake_size])
# 显示分数的函数
def show_score(score):
text = font.render("分数:" + str(score), True, black)
screen.blit(text, (10, 10))
# 游戏结束的函数
def game_over():
text = font.render("游戏结束!", True, red)
screen.blit(text, (width / 2 - 80, height / 2 - 20))
# 游戏循环
game_exit = False
clock = pygame.time.Clock()
snake_list = []
snake_length = 1
while not game_exit:
for event in pygame.event.get():
if event.type == pygame.QUIT:
game_exit = True
elif event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
direction = "left"
elif event.key == pygame.K_RIGHT:
direction = "right"
elif event.key == pygame.K_UP:
direction = "up"
elif event.key == pygame.K_DOWN:
direction = "down"
# 移动蛇的位置
if direction == "right":
snake_x += snake_speed
elif direction == "left":
snake_x -= snake_speed
elif direction == "up":
snake_y -= snake_speed
elif direction == "down":
snake_y += snake_speed
# 判断蛇是否吃到食物
if snake_x == food_x and snake_y == food_y:
food_x = round(random.randrange(0, width - snake_size) / 10.0) * 10.0
food_y = round(random.randrange(0, height - snake_size) / 10.0) * 10.0
snake_length += 1
score += 10
# 绘制游戏界面
screen.fill(white)
pygame.draw.rect(screen, red, [food_x, food_y, snake_size, snake_size])
snake_head = []
snake_head.append(snake_x)
snake_head.append(snake_y)
snake_list.append(snake_head)
if len(snake_list) > snake_length:
del snake_list[0]
for each in snake_list[:-1]:
if each == snake_head:
game_over()
draw_snake(snake_size, snake_list)
show_score(score)
pygame.display.update()
# 判断蛇是否撞到边界
if snake_x >= width or snake_x < 0 or snake_y >= height or snake_y < 0:
game_over()
# 控制游戏帧率
clock.tick(15)
# 退出 pygame
pygame.quit()
```
以上就是一个简单的贪吃蛇小游戏代码,希望能够帮到你。