用C++和QT来做一个最小路径和问题的可视化
时间: 2023-11-27 12:52:34 浏览: 52
最小路径和问题是一个经典的动态规划问题,可以用QT来可视化它。以下是一个简单的C++程序来计算和可视化最小路径和问题:
```c++
#include <QApplication>
#include <QWidget>
#include <QPushButton>
#include <QGridLayout>
#include <QLabel>
#include <vector>
const int INF = 10000000;
class MinPathWidget : public QWidget
{
Q_OBJECT
public:
MinPathWidget(QWidget *parent = 0);
~MinPathWidget();
public slots:
void calculate();
private:
QLabel *m_resultLabel;
std::vector<std::vector<int>> m_grid;
};
MinPathWidget::MinPathWidget(QWidget *parent)
: QWidget(parent)
{
m_resultLabel = new QLabel("Result: ");
QPushButton *calculateButton = new QPushButton("Calculate");
connect(calculateButton, SIGNAL(clicked()), this, SLOT(calculate()));
QGridLayout *layout = new QGridLayout;
layout->addWidget(m_resultLabel, 0, 0);
layout->addWidget(calculateButton, 1, 0);
setLayout(layout);
// initialize the grid with random values
m_grid.resize(5);
for (int i = 0; i < 5; ++i) {
m_grid[i].resize(5);
for (int j = 0; j < 5; ++j) {
m_grid[i][j] = qrand() % 10;
}
}
}
MinPathWidget::~MinPathWidget()
{
}
void MinPathWidget::calculate()
{
int n = m_grid.size();
std::vector<std::vector<int>> dp(n, std::vector<int>(n, INF));
dp[0][0] = m_grid[0][0];
for (int i = 1; i < n; ++i) {
dp[i][0] = dp[i-1][0] + m_grid[i][0];
}
for (int j = 1; j < n; ++j) {
dp[0][j] = dp[0][j-1] + m_grid[0][j];
}
for (int i = 1; i < n; ++i) {
for (int j = 1; j < n; ++j) {
dp[i][j] = std::min(dp[i-1][j], dp[i][j-1]) + m_grid[i][j];
}
}
m_resultLabel->setText(QString("Result: %1").arg(dp[n-1][n-1]));
}
int main(int argc, char *argv[])
{
QApplication app(argc, argv);
MinPathWidget widget;
widget.show();
return app.exec();
}
#include "main.moc"
```
这个程序使用QT来创建一个简单的GUI界面,包括一个标签来显示结果和一个按钮来计算最小路径和。在构造函数中,我们初始化了一个大小为5x5的随机网格,并将其存储在一个二维向量中。在calculate()函数中,我们使用动态规划来计算最小路径和,并将结果显示在标签中。