保留3位小数的浮点数
时间: 2023-12-23 22:58:09 浏览: 102
可以使用round()函数来保留浮点数的小数位数。以下是一个示例代码:
```python
num = 3.1415926
rounded_num = round(num, 3)
print(rounded_num) # 输出: 3.142
```
在这个例子中,我们将浮点数`num`保留到小数点后3位,并将结果存储在`rounded_num`变量中。然后,我们使用print()函数来显示结果。
相关问题
1024:保留3位小数的浮点数
题目要求保留3位小数的浮点数。可以使用`printf`函数来实现这个功能。具体的代码如下所示:
```c++
#include <iostream>
#include <cstdio>
using namespace std;
int main() {
double num;
scanf("%lf",
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保留12位小数的浮点数
保留12位小数的浮点数可以通过使用printf函数进行格式化输出。使用%.12lf的格式化字符串,可以将浮点数保留12位小数并输出。这样,输入的浮点数就能以保留12位小数的形式输出。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
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