c2000 fft代码
时间: 2023-06-21 14:21:20 浏览: 184
以下是C2000的FFT代码示例:
```c
#include "F28x_Project.h"
#include "math.h"
#define N 32
#define PI 3.14159265358979323846
#pragma DATA_SECTION(x, "ramgs0")
#pragma DATA_SECTION(y, "ramgs1")
#pragma DATA_SECTION(w, "ramgs2")
float x[N], y[N];
float w[N];
int main(void)
{
InitSysCtrl();
InitGpio();
int i;
// Generate input signal
for (i = 0; i < N; i++)
{
x[i] = sin(2 * PI * i / N) + 0.5 * sin(4 * PI * i / N);
y[i] = 0;
}
// Generate twiddle factors
for (i = 0; i < N; i++)
{
w[i] = cos(2 * PI * i / N) - sin(2 * PI * i / N) * I;
}
// Perform FFT
fft(x, y, w, N);
// Print output
for (i = 0; i < N; i++)
{
printf("X[%d] = %.4f + %.4fj\n", i, x[i], y[i]);
}
while(1) {}
}
void fft(float *x, float *y, float *w, int n)
{
int i, j, k, n1, n2;
float xr, xi, yr, yi;
// Bit-reverse the input
j = 0;
for (i = 0; i < n - 1; i++)
{
if (i < j)
{
xr = x[j];
xi = y[j];
x[j] = x[i];
y[j] = y[i];
x[i] = xr;
y[i] = xi;
}
k = n / 2;
while (k <= j)
{
j -= k;
k /= 2;
}
j += k;
}
// Perform the FFT
n1 = 0;
n2 = 1;
for (i = 0; i < log2(n); i++)
{
n1 = n2;
n2 *= 2;
for (j = 0; j < n1; j++)
{
for (k = j; k < n; k += n2)
{
xr = x[k];
xi = y[k];
yr = creal(w[i * n / n2]) * x[k + n1] - cimag(w[i * n / n2]) * y[k + n1];
yi = creal(w[i * n / n2]) * y[k + n1] + cimag(w[i * n / n2]) * x[k + n1];
x[k] = xr + yr;
y[k] = xi + yi;
x[k + n1] = xr - yr;
y[k + n1] = xi - yi;
}
}
}
}
```
这个代码使用了C语言标准库和C2000的DSP库来实现FFT。输入信号是一个长度为N的实数数组,输出是一个长度为N的复数数组。在代码中,`fft`函数实现了FFT算法,`x`和`y`数组存储输入和输出数据,`w`数组存储旋转因子。在主函数中,先生成输入信号,然后调用`fft`函数计算FFT,最后输出结果。
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