c语言实现给定一个字符串，你需要反转字符串中每个单词的字符顺序，同时仍保留空格和单词的初 始顺序。 输入: "Let's take LeetCode contest" 输出: "s'teL ekat edoCteeL tsetnoc"

以下是C语言实现给定一个字符串，反转字符串中每个单词的字符顺序，同时仍保留空格和单词的初始顺序的代码：

#include <stdio.h>
#include <string.h>

void reverse(char *s, int start, int end) {
    while (start < end) {
        char temp = s[start];
        s[start++] = s[end];
        s[end--] = temp;
    }
}

char *reverseWords(char *s) {
    int len = strlen(s);
    int start = 0, end = 0;
    while (end <= len) {
        if (s[end] == ' ' || s[end] == '\0') {
            reverse(s, start, end - 1);
            start = end + 1;
        }
        end++;
    }
    return s;
}

int main() {
    char s[] = "Let's take LeetCode contest";
    printf("%s\n", reverseWords(s));
    return 0;
}

输出结果为："s'teL ekat edoCteeL tsetnoc"