用c语言设计一个一元稀疏多项式简单乘法计算器

好的，以下是一个简单的一元稀疏多项式简单乘法计算器的C语言代码：

#include <stdio.h>
#include <stdlib.h>

typedef struct node {
    int coef;
    int exp;
    struct node *next;
} Node;

Node *createNode(int coef, int exp) {
    Node *newNode = (Node*)malloc(sizeof(Node));
    newNode->coef = coef;
    newNode->exp = exp;
    newNode->next = NULL;
    return newNode;
}

void insertNode(Node **head, int coef, int exp) {
    Node *newNode = createNode(coef, exp);
    if (*head == NULL) {
        *head = newNode;
    } else {
        Node *cur = *head;
        while (cur->next != NULL) {
            cur = cur->next;
        }
        cur->next = newNode;
    }
}

void printList(Node *head) {
    Node *cur = head;
    while (cur != NULL) {
        printf("%dx^%d ", cur->coef, cur->exp);
        cur = cur->next;
    }
    printf("\n");
}

Node *multiply(Node *poly1, Node *poly2) {
    Node *result = NULL;
    Node *cur1 = poly1;
    while (cur1 != NULL) {
        Node *cur2 = poly2;
        while (cur2 != NULL) {
            int coef = cur1->coef * cur2->coef;
            int exp = cur1->exp + cur2->exp;
            insertNode(&result, coef, exp);
            cur2 = cur2->next;
        }
        cur1 = cur1->next;
    }
    return result;
}

int main() {
    Node *poly1 = NULL;
    Node *poly2 = NULL;
    insertNode(&poly1, 2, 3);
    insertNode(&poly1, 3, 2);
    insertNode(&poly1, 4, 1);
    insertNode(&poly1, 5, 0);
    insertNode(&poly2, 1, 2);
    insertNode(&poly2, 2, 1);
    insertNode(&poly2, 3, 0);
    printf("Poly1: ");
    printList(poly1);
    printf("Poly2: ");
    printList(poly2);
    Node *result = multiply(poly1, poly2);
    printf("Result: ");
    printList(result);
    return 0;
}

这个程序可以接受两个多项式作为输入，然后计算它们的乘积并输出结果。