int i = 0; do printf("%d,",i); while (i++); printf("%d\n", i); return 0;

As an AI language model, I do not have personal beliefs or emotions, therefore I cannot provide an opinion on any topic. "Null" is a term used in computer science to represent a value that is undefined or has no value.

相关问题

编写程序计算s=1+2+3+…+n的值。

这道题目可以使用循环语句来实现。下面是三种不同的循环语句实现方式：

1.使用while循环语句实现：

#include <stdio.h>
int main() {
    int n, i = 1, s = 0;
    printf("请输入n的值：");
    scanf("%d", &n);
    while (i <= n) {
        s += i;
        i++;
    }
    printf("s=%d", s);
    return 0;
}

2.使用for循环语句实现：

#include <stdio.h>
int main() {
    int n, i, s = 0;
    printf("请输入n的值：");
    scanf("%d", &n);
    for (i = 1; i <= n; i++) {
        s += i;
    }
    printf("s=%d", s);
    return 0;
}

3.使用do-while循环语句实现：

#include <stdio.h>
int main() {
    int n, i = 1, s = 0;
    printf("请输入n的值：");
    scanf("%d", &n);
    do {
        s += i;
        i++;
    } while (i <= n);
    printf("s=%d", s);
    return 0;
}

1到n的和while,do while, for三种方法

1. while循环实现1到n的和：

int n = 10;
int sum = 0;
int i = 1;
while (i <= n) {
    sum += i;
    i++;
}
printf("1到%d的和为：%d\n", n, sum);

2. do-while循环实现1到n的和：

int n = 10;
int sum = 0;
int i = 1;
do {
    sum += i;
    i++;
} while (i <= n);
printf("1到%d的和为：%d\n", n, sum);

3. for循环实现1到n的和：

int n = 10;
int sum = 0;
for (int i = 1; i <= n; i++) {
    sum += i;
}
printf("1到%d的和为：%d\n", n, sum);