c#时间戳转换日期格式输出

在C#中，可以使用以下代码将时间戳转换为日期格式输出：

using System;
using UnityEngine;

private void Start() 
{
    DateTime dateTime = TimestampHelper.GetDateTime(1482115779);
    Debug.Log(dateTime.Year + "年" + dateTime.Month + "月" + dateTime.Day + "日");
    DateTime dateTime_2 = TimestampHelper.GetDateTime("1482115779");
    Debug.Log(dateTime_2.Hour + "：" + dateTime.Minute + "：" + dateTime.Second);
}

public static DateTime GetTime(long TimeStamp, bool AccurateToMilliseconds = false) 
{
    System.DateTime startTime = TimeZone.CurrentTimeZone.ToLocalTime(new System.DateTime(1970, 1, 1)); // 当地时区
    if (AccurateToMilliseconds) 
    {
        return startTime.AddTicks(TimeStamp * 10000);
    } 
    else 
    {
        return startTime.AddTicks(TimeStamp * 10000000);
    }
}

这段代码使用了一个名为`TimestampHelper`的静态类来实现时间戳转换日期的功能。在`Start()`方法中，我们首先使用`TimestampHelper.GetDateTime()`方法将时间戳转换为`DateTime`类型的日期时间对象，然后通过访问`DateTime`对象的属性来获取具体的年、月、日等信息，并通过`Debug.Log()`方法将其输出。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
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