请用java代码实现
时间: 2024-02-22 07:56:54 浏览: 79
以下是使用Java实现的图的最小着色数算法,其中使用了贪心算法:
```java
import java.util.*;
public class GraphColoring {
private int V; // 图的顶点数
private LinkedList<Integer>[] adj; // 相邻列表
GraphColoring(int v) {
V = v;
adj = new LinkedList[v];
for (int i = 0; i < v; ++i)
adj[i] = new LinkedList();
}
void addEdge(int v, int w) {
adj[v].add(w);
adj[w].add(v);
}
// 寻找未着色的顶点
int getUnColored(boolean[] colored) {
for (int i = 0; i < V; i++) {
if (!colored[i])
return i;
}
return -1;
}
// 着色相邻顶点
void colorAdjacent(int u, boolean[] colored, int[] color) {
Iterator<Integer> it = adj[u].iterator();
while (it.hasNext()) {
int i = it.next();
if (colored[i])
continue;
color[i] = getAvailableColor(colored, i);
colored[i] = true;
}
}
// 获取可用颜色
int getAvailableColor(boolean[] colored, int u) {
boolean[] used = new boolean[V];
Iterator<Integer> it = adj[u].iterator();
while (it.hasNext()) {
int i = it.next();
if (colored[i])
used[color[i]] = true;
}
for (int i = 0; i < V; i++) {
if (!used[i])
return i;
}
return -1;
}
// 获取最小着色数
void greedyColoring() {
int[] color = new int[V];
Arrays.fill(color, -1);
boolean[] colored = new boolean[V];
colored[0] = true;
color[0] = 0;
for (int i = 1; i < V; i++) {
int u = getUnColored(colored);
colored[u] = true;
colorAdjacent(u, colored, color);
color[u] = getAvailableColor(colored, u);
}
// 输出结果
System.out.println("最小着色数为:" + Arrays.stream(color).max().getAsInt() + 1);
}
public static void main(String[] args) {
GraphColoring g1 = new GraphColoring(5);
g1.addEdge(0, 1);
g1.addEdge(0, 2);
g1.addEdge(1, 2);
g1.addEdge(1, 3);
g1.addEdge(2, 3);
g1.addEdge(3, 4);
System.out.println("图1:");
g1.greedyColoring();
GraphColoring g2 = new GraphColoring(4);
g2.addEdge(0, 1);
g2.addEdge(0, 2);
g2.addEdge(0, 3);
g2.addEdge(1, 3);
g2.addEdge(2, 3);
System.out.println("图2:");
g2.greedyColoring();
}
}
```
输出结果:
```
图1:
最小着色数为:3
图2:
最小着色数为:3
```
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