第一个SQL: SELECT orders.id,orders.user_id,orders.cityarea_id,orders.batchcode,orders.status, orders.pay_status,orders.real_pay,orders.total,orders.money,orders.pay_type, orders.premium,orders.createtime,orders.paytime,orders.confirmtime, orders.is_evaluate,orders.pay_method,orders.exp_user_id, orders.return_score, orders.is_change,orders.reward_money,orders.isvalid,orders.after_sale_status,orders.remark, orders.use_coupon_detail,orders.block_chain_price, users.name,users.weixin_name,users.weixin_fromuser, users.phone,wcoe.diy_area_name from wsy_o2o.weixin_cityarea_orders orders left join wsy_o2o.weixin_cityarea_supply supply on orders.cityarea_id = supply.id left join wsy_o2o.weixin_cityarea_payonline_orders wcco on orders.batchcode=wcco.batchcode left join wsy_user.weixin_users users on users.id = orders.user_id LEFT JOIN wsy_o2o.weixin_cityarea_orders_extend wcoe ON orders.batchcode = wcoe.batchcode WHERE orders.types=3 and orders.customer_id = 41 AND orders.isvalid=true GROUP BY orders.batchcode ORDER BY orders.id DESC limit 0,20; 第二个SQL: SELECT orders.id,orders.user_id,orders.cityarea_id,orders.batchcode,orders.status, orders.pay_status,orders.real_pay,orders.total,orders.money,orders.pay_type, orders.premium,orders.createtime,orders.paytime,orders.confirmtime, orders.is_evaluate,orders.pay_method,orders.exp_user_id, orders.return_score, orders.is_change,orders.reward_money,orders.isvalid,orders.after_sale_status,orders.remark, orders.use_coupon_detail,orders.block_chain_price, users.name,users.weixin_name,users.weixin_fromuser, users.phone,wcoe.diy_area_name ,writes.ActivityStatus,writes.NewMoney from wsy_o2o.weixin_cityarea_orders orders left join wsy_o2o.weixin_cityarea_supply supply on orders.cityarea_id = supply.id left join wsy_o2o.weixin_cityarea_payonline_orders wcco on orders.batchcode=wcco.batchcode left join wsy_user.weixin_users users on users.id = orders.user_id LEFT JOIN wsy_o2o.weixin_cityarea_orders_extend wcoe ON orders.batchcode = wcoe.batchcode LEFT JOIN wsy_dream.ShopWrite writes on orders.batchcode = writes.Batchcode WHERE orders.types=3 and orders.customer_id = 41 AND orders.isvalid=true GROUP BY orders.batchcode ORDER BY orders.id DESC limit 0,20; 为什么查询结果从0.7秒变成了3.7秒?
时间: 2024-04-10 15:31:49 浏览: 133
查询结果从0.7秒变成3.7秒可能是由于以下原因导致的:
1. SQL语句中的表连接(JOIN)操作过多:第二个SQL语句相较于第一个SQL语句多了一个表连接,即LEFT JOIN wsy_dream.ShopWrite writes on orders.batchcode = writes.Batchcode。表连接操作会增加查询的复杂度和执行时间。
2. 数据量增加:第二个SQL语句可能查询的数据量较第一个SQL语句更多,这会导致查询时间增加。
3. 索引缺失或失效:如果查询涉及的列没有合适的索引或索引失效,数据库会执行全表扫描,导致查询时间增加。
4. 数据库服务器负载增加:查询较繁忙的时候,数据库服务器的负载可能增加,导致查询时间延长。
为了确定具体原因,可以进一步分析数据库执行计划、索引情况以及服务器负载情况。
相关问题
select count(*) FROM xgb_order_products op LEFT JOIN xgb_orders o ON o.order_id=op.order_id left join xgb_order_after_sales oas on op.order_id = oas.order_id where (op.all_refund = 0 or (oas.type = 2 and oas.status = 5) and o.status = 4 and op.is_comment = 0 and o.user_id = 492740 and op.is_gift = 0
这是一个有效的 SQL 查询语句,它的作用是统计满足一定条件的订单商品数量。该查询语句的条件如下:
- 订单商品表 xgb_order_products 中的 all_refund 字段等于 0;
- 订单表 xgb_orders 中的 status 等于 4,user_id 等于 492740;
- 订单商品表 xgb_order_products 中的 is_comment 字段等于 0,is_gift 字段等于 0;
- 订单售后表 xgb_order_after_sales 中的 type 等于 2,status 等于 5。
该查询语句可以根据你的具体需求进行修改。
User::with([ 'adviser' => function ($query) { $query->select('id', 'name'); }, 'job_log' => function ($query) { $query->select('id', 'sex'); }, 'journal' => function ($query) { $query->select('id', 'name'); }, 'order' => function ($query) { $query->select('user_id', DB::raw("COUNT(*) AS num"), DB::raw("SUM(CASE WHEN status = 2 THEN 1 ELSE 0 END ) AS appropriation_num"), DB::raw("SUM(CASE WHEN status = 2 THEN appropriation_amount ELSE 0 END ) AS appropriation_sum"), DB::raw("SUM(CASE WHEN status = 5 THEN 1 ELSE 0 END ) AS net_income_num"), DB::raw("SUM(CASE WHEN status = 5 THEN net_income ELSE 0 END ) AS net_income_sum")) ->groupBy('user_id'); } ]) ->select('id') ->where('id', $post['id']) ->first();转换成sql语句
这个 Eloquent 查询语句会查询出 ID 为 `$post['id']` 的用户,并预加载它们的 `adviser`、`job_log`、`journal` 和 `order` 关联模型,其中 `order` 模型会使用聚合函数进行统计。下面是这个查询语句转换成 SQL 的样子:
```sql
select `id`
from `users`
where `id` = ?
limit 1
select `id`, `name`
from `advisers`
where `advisers`.`user_id` in (?)
select `id`, `sex`
from `job_logs`
where `job_logs`.`user_id` in (?)
select `id`, `name`
from `journals`
where `journals`.`user_id` in (?)
select `user_id`, COUNT(*) AS num,
SUM(CASE WHEN status = 2 THEN 1 ELSE 0 END) AS appropriation_num,
SUM(CASE WHEN status = 2 THEN appropriation_amount ELSE 0 END) AS appropriation_sum,
SUM(CASE WHEN status = 5 THEN 1 ELSE 0 END) AS net_income_num,
SUM(CASE WHEN status = 5 THEN net_income ELSE 0 END) AS net_income_sum
from `orders`
where `orders`.`user_id` in (?)
group by `user_id`
```
其中 `?` 是绑定参数,值取决于查询语句中的占位符数量。这个查询语句会先查询出 ID 为 `$post['id']` 的用户,然后再分别查询出它们的 `adviser`、`job_log`、`journal` 和 `order` 关联模型,其中 `order` 模型会使用聚合函数进行统计。