检查一下SQL代码有没有错误，有的话标识出来并且改错：SET FOREIGN_KEY_CHECKS = 0; DROP TABLE IF EXISTS employee_info; CREATE TABLE employee_info ( e_id int(0) NOT NULL COMMENT '工作人员编号', e_name varchar(50) NOT NULL COMMENT '工作人员姓名', m_id int(0) NOT NULL COMMENT '管理员编号', PRIMARY KEY (e_id) USING BTREE, INDEX m_id(m_id) USING BTREE, CONSTRAINT m_id FOREIGN KEY (m_id) REFERENCES hotel_manager_info (m_id) ON DELETE CASCADE ON UPDATE CASCADE ) ; DROP TABLE IF EXISTS hotel_info; CREATE TABLE hotel_info ( h_id int(0) NOT NULL COMMENT '酒店序号', h_name varchar(25) NOT NULL COMMENT '酒店名称', h_address varchar(255) NOT NULL COMMENT '酒店地址', h_phone varchar(50) NOT NULL COMMENT '酒店电话', o_statistics int(0) NULL DEFAULT NULL COMMENT '统计订单量', PRIMARY KEY (h_id) USING BTREE ) ; DROP TABLE IF EXISTS hotel_manager_info; CREATE TABLE hotel_manager_info ( m_id int(0) NOT NULL COMMENT '管理员编号', m_name varchar(50) NOT NULL COMMENT '管理员姓名', h_id int(0) NULL DEFAULT NULL COMMENT '酒店序号', PRIMARY KEY (m_id) USING BTREE, INDEX hotel_id(h_id) USING BTREE, CONSTRAINT hotel_id FOREIGN KEY (h_id) REFERENCES hotel_info (h_id) ON DELETE CASCADE ON UPDATE CASCADE ) ; DROP TABLE IF EXISTS order_info; CREATE TABLE order_info ( o_id int(0) NOT NULL COMMENT '订单编号', r_id int(0) NOT NULL COMMENT '房间号', u_id int(0) NOT NULL COMMENT '用户id', o_checkin_time datetime(0) NULL DEFAULT NULL COMMENT '入住时间', o_checkout_time datetime(0) NOT NULL COMMENT '离开时间', o_status enum('not null',"null") NULL DEFAULT NULL COMMENT '为null 时表示未入住', PRIMARY KEY (o_id) USING BTREE, INDEX r_id(r_id) USING BTREE, INDEX u_id(u_id) USING BTREE, CONSTRAINT r_id FOREIGN KEY (r_id) REFERENCES room_info (r_id) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT u_id FOREIGN KEY (u_id) REFERENCES user_info (u_id) ON DELETE CASCADE ON UPDATE CASCADE ) ; DROP TABLE IF EXISTS room_info; CREATE TABLE room_info ( r_id int(0) NOT NULL COMMENT '房间号', r_name varchar(50) NOT NULL COMMENT '房间名称', r_type varchar(50) NOT NULL COMMENT '房间类型', r_price varchar(50) NULL DEFAULT NULL COMMENT '房间价格', h_id int(0) NOT NULL COMMENT '酒店序号', PRIMARY KEY (r_id) USING BTREE, INDEX h_id(h_id) USING BTREE, CONSTRAINT h_id FOREIGN KEY (h_id) REFERENCES hotel_info (h_id) ON DELETE CASCADE ON UPDATE CASCADE ) ; DROP TABLE IF EXISTS user_info; CREATE TABLE user_info ( u_id int(0) NOT NULL COMMENT '用户编号', u_name varchar(50) NOT NULL COMMENT '用户名', u_password varchar(50) NOT NULL COMMENT '密码', u_phone varchar(50) NULL DEFAULT NULL COMMENT '手机号码', u_email varchar(50) NULL DEFAULT NULL COMMENT '邮箱', u_register_time datetime(0) NULL DEFAULT NULL COMMENT '注册时间', PRIMARY KEY (u_id) USING BTREE ) ; SET FOREIGN_KEY_CHECKS = 1;

在以下语句中，'not null' 应该改为 'not_null'：

o_status enum('not_null',"null") NULL DEFAULT NULL COMMENT '为null 时表示未入住'

应该改为：

o_status enum('not_null','null') NULL DEFAULT NULL COMMENT '为null时表示未入住'

相关问题

if set_time_H == now_time_H: if set_time_M == now_time_M: if set_time_S == now_time_S: print("该起床了...") try: playsound('') except Exceptiopn as e: print(e) break elif set_time_H <= now_time_H: print('你设置的时间不在当天') break

else:
print('你设置的时间还没到')
break

This code checks if the set alarm time (set_time_H, set_time_M, set_time_S) is equal to the current time (now_time_H, now_time_M, now_time_S). If they are equal, it prints "该起床了..." and tries to play a sound. If the set time is earlier than the current time (set_time_H <= now_time_H), it prints "你设置的时间不在当天". If the set time is later than the current time, it prints "你设置的时间还没到". In both cases it breaks out of the loop.

set foreign_key_checks=0

set foreign_key_checks= 是MySQL的一条SQL语句，用于关闭MySQL数据库的外键约束检查功能。当设置为时，MySQL将不会检查外键约束，允许用户在不满足外键约束的情况下插入、更新或删除数据。这个命令通常用于导入数据时，可以避免由于外键约束导致的插入、更新或删除失败的情况。但是，使用此命令需要谨慎，因为关闭外键约束可能会导致数据不一致。