*** ** * 用python编写
时间: 2023-10-06 12:13:00 浏览: 37
***是一个迷宫,其中*代表障碍物。可以使用A*算法来寻找从起点到终点的最优路径。下面是一个使用python编写的示例代码:
```python
def A_star(maze):
# 在地图中找到起点和终点的位置
start = find_start(maze)
end = find_end(maze)
# 初始化起点的代价和估计代价
start.g = 0
start.h = heuristic(start, end)
start.f = start.g + start.h
# 创建一个优先队列,用于存储待扩展的节点
open_list = PriorityQueue()
open_list.put(start)
# 创建一个集合,用于存储已经访问过的节点
closed_set = set()
while not open_list.empty():
# 从优先队列中取出f值最小的节点
current = open_list.get()
# 如果当前节点是终点,说明找到了最优路径
if current == end:
return reconstruct_path(current)
# 将当前节点标记为已访问
closed_set.add(current)
# 扩展当前节点的邻居节点
for neighbor in get_neighbors(current, maze):
if neighbor in closed_set:
continue
# 计算邻居节点的代价和估计代价
g_score = current.g + 1
h_score = heuristic(neighbor, end)
f_score = g_score + h_score
if neighbor.f is None or f_score < neighbor.f:
neighbor.g = g_score
neighbor.h = h_score
neighbor.f = f_score
neighbor.parent = current
if neighbor not in open_list.queue:
open_list.put(neighbor)
# 如果优先队列为空且没有找到终点,说明无法到达终点
return "无法找到最优路径"
# 测试样例
maze = [
['*', '*', '*', '*', '*', '*', '*', '*', '*', '*'],
['*', ' ', ' ', ' ', '*', ' ', ' ', ' ', ' ', '*'],
['*', ' ', '*', ' ', '*', '*', '*', ' ', ' ', '*'],
['*', ' ', '*', ' ', ' ', ' ', '*', ' ', ' ', '*'],
['*', ' ', '*', '*', '*', ' ', '*', '*', ' ', '*'],
['*', ' ', ' ', ' ', '*', ' ', ' ', ' ', ' ', '*'],
['*', '*', '*', '*', '*', '*', '*', '*', '*', '*']
]
result = A_star(maze)
print(result)
```