python 比较大小 容差 0.001

可以使用Python中的abs()函数来比较两个数的大小，并设置一个容差值。具体实现如下所示：

def compare_with_tolerance(a, b, tolerance):
    if abs(a - b) < tolerance:
        print("a and b are equal within the tolerance of", tolerance)
    elif a > b:
        print("a is greater than b by more than the tolerance of", tolerance)
    else:
        print("b is greater than a by more than the tolerance of", tolerance)

# 示例
compare_with_tolerance(1.0001, 1.0002, 0.001) # 输出：a and b are equal within the tolerance of 0.001
compare_with_tolerance(1.0001, 1.0003, 0.001) # 输出：a is greater than b by more than the tolerance of 0.001
compare_with_tolerance(1.0003, 1.0001, 0.001) # 输出：b is greater than a by more than the tolerance of 0.001