将文件中的代码转换成c++代码,功能不变
时间: 2024-11-11 14:33:30 浏览: 4
零相位双边滤波器matlab/C++代码
将给定的Python代码转换为C++代码需要考虑以下几个方面:
1. **库的替换**:OpenCV在Python和C++中的API有差异,需要进行相应的调整。
2. **语法差异**:Python和C++在语法上有显著不同,例如循环、条件语句等。
3. **数据类型的管理**:C++是静态类型语言,需要显式声明变量类型。
4. **错误处理**:C++通常使用异常处理机制来处理错误。
以下是将给定的Python代码转换为C++代码的示例:
```cpp
#include <opencv2/opencv.hpp>
#include <iostream>
#include <vector>
#include <cmath>
using namespace cv;
using namespace std;
// 定义常量
const int jifen = 5;
const int daodianju = 3;
const float feichezhanbi = 0.73;
const int yuanhuanyuzhi = 40;
const int yuanhuanjingdu = 10;
const int kuanzeng = 90;
const int kuanzeng2 = 70;
const int CAMERA_H = 60;
const int CAMERA_W = 94;
const int OUT_H = 60;
const int OUT_W = 94;
// 全局变量
int shiziji = 0;
int banmasign = 0;
// 结构体定义
struct Up {
Point dian;
int que;
};
// 图像二值化
Mat er_zhi(Mat imgxiu) {
try {
Mat imgCvt, imgTemp, imgThr;
cvtColor(imgxiu, imgCvt, COLOR_BGR2GRAY);
GaussianBlur(imgCvt, imgTemp, Size(5, 5), 0);
threshold(imgTemp, imgThr, 0, 255, THRESH_BINARY + THRESH_OTSU);
if (imgThr.empty()) {
throw runtime_error("Thresholding failed, possibly due to invalid image data.");
}
return imgThr;
} catch (const exception& e) {
cerr << "An error occurred: " << e.what() << endl;
return Mat();
}
}
// 画出赛道两侧线和中线
void che_dao_xian(Mat imgEr, Mat& imgSour) {
vector<Up> zuoDao, youDao, zhongXian;
int shizipan = 0, yuanhuanzuosign = 0, yuanhuanyousign = 0;
vector<Point> yuanhuanweidian(4, Point(0, 0));
int high = static_cast<int>(imgEr.rows * feichezhanbi);
// 获取每一列白色点数据
vector<int> lieBais(imgEr.cols, 0);
for (int x = 0; x < imgEr.cols; ++x) {
for (int y = high - 1; y >= 0; --y) {
if (imgEr.at<uchar>(y, x) != 0) {
lieBais[x]++;
} else {
break;
}
}
}
// 寻找左右最长白条
int maxzuo[] = {0, 0};
int maxyou[] = {0, 0};
for (int a = 0; a < lieBais.size(); ++a) {
if (lieBais[a] > maxzuo[1]) {
maxzuo[0] = a;
maxzuo[1] = lieBais[a];
}
}
for (int a = lieBais.size() - 1; a >= 0; --a) {
if (lieBais[a] > maxyou[1]) {
maxyou[0] = a;
maxyou[1] = lieBais[a];
}
}
// 找车道线
int chushi = 0, chuju = 0, shiziZuox = 0, shiziYoux = 0;
for (int y = high - 1; y > high - maxzuo[1]; --y) {
int zuox = maxzuo[0];
for (int x = maxzuo[0]; x >= 0; --x) {
if (imgEr.at<uchar>(y, x) != 0 && imgEr.at<uchar>(y, x - 1) == 0) {
if (!zuoDao.empty()) {
double dist = norm(Point(x, y) - zuoDao.back().dian);
if (dist <= daodianju) {
zuoDao.push_back({Point(x, y), 0});
zuox = x;
break;
}
} else {
zuoDao.push_back({Point(x, y), 0});
zuox = x;
break;
}
} else if (imgEr.at<uchar>(y, x) != 0 && imgEr.at<uchar>(y, x - 1) != 0 && imgEr.at<uchar>(y, x - 2) != 0) {
shiziZuox++;
if (x - 3 == 0) {
break;
}
}
}
int tempx = maxyou[0];
for (int x = maxyou[0] + 5; x < imgEr.cols; ++x) {
if (imgEr.at<uchar>(y, x) != 0 && imgEr.at<uchar>(y, x + 1) == 0) {
if (!youDao.empty()) {
double dist = norm(Point(x, y) - youDao.back().dian);
if (dist <= daodianju) {
youDao.push_back({Point(x, y), 0});
tempx = x;
break;
}
} else {
youDao.push_back({Point(x, y), 0});
tempx = x;
break;
}
} else if (imgEr.at<uchar>(y, x) != 0 && imgEr.at<uchar>(y, x + 1) != 0 && imgEr.at<uchar>(y, x + 2) != 0) {
shiziYoux++;
if (x + 3 == imgEr.cols - 1) {
break;
}
}
}
if (chuju == 0) {
chuju = tempx - zuox;
}
if (abs(shiziZuox - maxzuo[0]) <= 5 && abs(imgEr.cols - maxyou[0] + 4 - shiziYoux) <= 5) {
shizipan = 1;
}
}
// 判断圆环存在否,及其位置
if (abs(static_cast<int>(zuoDao.size()) - static_cast<int>(youDao.size())) >= yuanhuanyuzhi) {
int ji1 = 0, ji2 = 0, signs = 0;
// 左圆环
if (zuoDao.size() < youDao.size()) {
int zuominx = 999999;
for (const auto& point : zuoDao) {
if (zuominx > point.dian.x) {
zuominx = point.dian.x;
}
}
for (size_t n = 0; n < youDao.size(); ++n) {
signs = 0;
for (int x = youDao[n].dian.x; x > max(zuominx - 5, 1); --x) {
if (imgEr.at<uchar>(youDao[n].dian.y, x) != 0 && imgEr.at<uchar>(youDao[n].dian.y, x - 1) == 0) {
if (yuanhuanyousign == 1 && ji1 >= 5) {
yuanhuanyousign = 2;
yuanhuanweidian[1] = Point(youDao[n - 5].dian.x - kuanzeng, youDao[n - 5].dian.y);
ji1 = 0;
} else if (yuanhuanyousign == 3 && ji1 >= 5) {
yuanhuanyousign = 4;
ji1 = 0;
break;
}
signs = 1;
ji1++;
ji2 = 0;
}
}
if (signs == 0) {
if (yuanhuanyousign == 0 && ji2 >= 5) {
yuanhuanyousign = 1;
yuanhuanweidian[0] = Point(youDao[n - 5].dian.x - kuanzeng, youDao[n - 5].dian.y);
ji2 = 0;
} else if (yuanhuanyousign == 2 && ji2 >= 5) {
yuanhuanyousign = 3;
ji2 = 0;
}
ji2++;
ji1 = 0;
}
}
}
// 右圆环
else {
int youmaxx = 0;
for (const auto& point : youDao) {
if (youmaxx < point.dian.x) {
youmaxx = point.dian.x;
}
}
for (size_t n = 0; n < zuoDao.size(); ++n) {
signs = 0;
for (int x = zuoDao[n].dian.x; x < youmaxx; ++x) {
if (imgEr.at<uchar>(zuoDao[n].dian.y, x) != 0 && imgEr.at<uchar>(zuoDao[n].dian.y, x + 1) == 0) {
if (yuanhuanzuosign == 1 && ji1 >= yuanhuanjingdu) {
yuanhuanzuosign = 2;
yuanhuanweidian[1] = Point(zuoDao[n - 5].dian.x + kuanzeng2, zuoDao[n - 5].dian.y);
ji1 = 0;
} else if (yuanhuanzuosign == 3 && ji1 >= yuanhuanjingdu) {
yuanhuanzuosign = 4;
ji1 = 0;
break;
}
signs = 1;
ji1++;
ji2 = 0;
}
}
if (signs == 0) {
if (yuanhuanzuosign == 0 && ji2 >= yuanhuanjingdu) {
yuanhuanzuosign = 1;
yuanhuanweidian[0] = Point(zuoDao[n - 5].dian.x + kuanzeng2 + 10, zuoDao[n - 5].dian.y);
ji2 = 0;
} else if (yuanhuanzuosign == 2 && ji2 >= yuanhuanjingdu) {
yuanhuanzuosign = 3;
ji2 = 0;
}
ji2++;
ji1 = 0;
}
}
}
// 圆环判断
if (yuanhuanzuosign == 4) {
putText(imgSour, "right circular", Point(10, 40), FONT_HERSHEY_COMPLEX, 0.7, Scalar(0, 0, 255), 2);
for (int n = 0; n < 2; ++n) {
line(imgSour, Point(imgEr.cols - 1, yuanhuanweidian[n].y), yuanhuanweidian[n], Scalar(255, 0, 255), 3.5);
}
} else if (yuanhuanyousign == 4) {
putText(imgSour, "left circular", Point(10, 40), FONT_HERSHEY_COMPLEX, 0.7, Scalar(0, 0, 255), 2);
for (int n = 0; n < 2; ++n) {
line(imgSour, Point(0, yuanhuanweidian[n].y), yuanhuanweidian[n], Scalar(255, 0, 255), 3.5);
}
}
}
// 找中线
size_t sizes = min(zuoDao.size(), youDao.size());
for (size_t n = 0; n < sizes; ++n) {
if (zuoDao[n].que == 0 && youDao[n].que == 0) {
int zhongx = (zuoDao[n].dian.x + youDao[n].dian.x) / 2;
int zhongy = (zuoDao[n].dian.y + youDao[n].dian.y) / 2;
if (zhongXian.empty() || (abs(zhongx - zhongXian.back().dian.x) <= daodianju && abs(zhongy - zhongXian.back().dian.y) >= 2)) {
zhongXian.push_back({Point(zhongx, zhongy), 0});
}
}
}
// 画出中线
for (size_t n = 0; n < zhongXian.size() - 1; ++n) {
circle(imgSour, zhongXian[n].dian, 2, Scalar(0, 255, 0), -1);
line(imgSour, zhongXian[n].dian, zhongXian[n + 1].dian, Scalar(0, 255, 0), 4);
}
// 画出车道线
for (const auto& point : zuoDao) {
circle(imgSour, point.dian, 2, Scalar(255, 0, 0), -1);
}
for (const auto& point : youDao) {
circle(imgSour, point.dian, 2, Scalar(0, 0, 255), -1);
}
}
int main() {
string video_file = "playground.mp4";
VideoCapture cap(video_file);
if (!cap.isOpened()) {
cerr << "Error opening video file." << endl;
return -1;
}
while (cap.isOpened()) {
Mat frame, frame2, f;
if (!cap.read(frame)) {
break;
}
try {
frame2 = er_zhi(frame);
che_dao_xian(frame2, frame);
imshow("Frame", frame);
if (waitKey(1) & 0xFF == 'q') {
break;
}
} catch (const exception& e) {
cerr << "Exception: " << e.what() << endl;
}
}
cap.release();
destroyAllWindows();
return 0;
}
```
### 主要变化点:
1. **库的导入**:从`#include <opencv2/opencv.hpp>`开始,引入了必要的OpenCV头文件。
2. **常量和全局变量**:直接用`const`关键字定义常量,并初始化全局变量。
3. **函数定义**:将Python的函数转换为C++的函数,注意参数和返回值类型的定义。
4. **数据类型**:所有变量都显式声明了类型。
5. **循环和条件语句**:C++中的循环和条件语句与Python类似,但需要注意语法上的细微差别。
6. **错误处理**:使用`try-catch`块来捕获和处理异常。
希望这段C++代码能够满足你的需求。如果有任何问题或需要进一步优化,请告诉我!
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