C语言求五个人三门课的平均成绩

在C语言中，我们可以创建一个结构体来存储每个人的成绩，然后计算五个人三门课程的总成绩和平均分。这里是一个简单的示例：

#include <stdio.h>

// 定义学生结构体
typedef struct {
    char name[50];
    int math_score;
    int science_score;
    int english_score;
} Student;

// 求单科平均分函数
double calculate_average(int score) {
    return (double)score / 100; // 假设满分是100分
}

int main() {
    const int num_students = 5;
    const int num_courses = 3;
    Student students[num_students];

    for (int i = 0; i < num_students; i++) {
        printf("请输入第%d位学生的姓名、数学、科学和英语成绩：\n", i + 1);
        scanf("%s %d %d %d", students[i].name, &students[i].math_score, &students[i].science_score, &students[i].english_score);
    }

    double total_scores[num_courses] = {0}; // 存储各科总分
    for (int j = 0; j < num_courses; j++) {
        for (int k = 0; k < num_students; k++) {
            total_scores[j] += students[k].scores[j]; // 提供了一个scores数组作为实际分数访问
        }
    }

    double overall_average = 0;
    for (int l = 0; l < num_courses; l++) {
        overall_average += calculate_average(total_scores[l]);
    }
    overall_average /= num_courses;

    printf("五个人三门课程的平均成绩是: %.2f\n", overall_average);

    return 0;
}