输入年月日，显示这一天是这一年第几天

以下是两种实现输入年月日，显示这一天是这一年第几天的方法：

方法一：使用C语言实现

#include <stdio.h>
int main() {
    int year, month, day;
    int days = 0;
    scanf("%d%d%d", &year, &month, &day);
    days += day;
    switch(month) {
        case 12: days += 30;
        case 11: days += 31;
        case 10: days += 30;
        case 9: days += 31;
        case 8: days += 31;
        case 7: days += 30;
        case 6: days += 31;
        case 5: days += 30;
        case 4: days += 31;
        case 3:
            if(((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)) days += 29;
            else days += 28;
        case 2: days += 31;
    }
    printf("%d\n", days);
    return 0;
}

方法二：使用Python实现

x = int(input("请输入年份："))
y = int(input("请输入月份："))
z = int(input("请输入日期："))
if x > 0 and y > 1 and y <= 12 and z > 0 and z <= 30:
    print(f"该日期是{x}年的第{(y-1)*30+z}天")
elif x > 0 and y == 1 and z > 0 and z <= 30:
    print(f"该日期是{x}年的第{z}天")