select [wrong_type],[reason],count(*) as 数量 from ( SELECT [id] ,[check_date] ,[checker] ,[inspected_person] ,[secondary_rework] ,[type] ,[project] ,[project_name] ,[NID] ,[wrong_type] ,[reason] ,[wrong_description] ,[complaint_status] ,[date] ,[create_time] FROM [DV_report].[dbo].[miss] where date>='${start}' and date<='${end}' and complaint_status='申诉后' and wrong_type not in ('无','建议') and inspected_person not in('DL001','DL002') UNION SELECT [id] ,[check_date] ,[checker] ,[secondary_rework] as [inspected_person] ,[inspected_person] as [secondary_rework] ,[type] ,[project] ,[project_name] ,[NID] ,[wrong_type] ,[reason] ,[wrong_description] ,[complaint_status] ,[date] ,[create_time] FROM [DV_report].[dbo].[miss] where date>='${start}' and date<='${end}' and complaint_status='申诉后' and wrong_type = '网络问题' and [reason] = '状态错误' and [inspected_person] is not null and [inspected_person] !='' and inspected_person not in('DL001','DL002') )as a group by [wrong_type],[reason] order by [wrong_type],[reason] 帮我将这段代码转换为postgre格式语言

select pro_income, count() as presence from property group by pro_income having count() >= all( select count(*) from property group by pro_income );

select pro_income, count(*) as presence from property group by pro_income having count(*) >= all( select count(*) from property group by pro_income ); 需要注意的是，此查询可能会影响...

SELECT area_attribute, count(*) as num FROM org_info GROUP BY area_attribute用LambdaQueryWrappe实现

SqlFunction.count(OrgInfo::getId).as("num")) .groupBy(OrgInfo::getAreaAttribute); List, Object>> results = orgInfoMapper.selectMaps(wrapper); 其中，OrgInfo是对应的实体类，orgInfoMapper是...

如何利用这个SQL进行删除这些公司出现次数-1的数量，只剩下一家这些公司SELECT company_name, COUNT() AS count FROM ( SELECT company_name, DENSE_RANK() OVER (ORDER BY company_name) AS company_rank FROM your_table_name ) AS subquery GROUP BY company_name HAVING COUNT() > 1;

SELECT company_name, COUNT(*) AS count FROM ( SELECT company_name, DENSE_RANK() OVER (ORDER BY company_name) AS company_rank FROM your_table_name ) AS subquery GROUP BY company_name ) AS ...

select b.[leader_name],[inspected_person],wrong_type,b.Departure_date,count() as miss数量 from ( select from ( select * ,row_number() over(partition by [check_date],[checker],[inspected_person],[secondary_rework],[type],[project],[project_name],[NID],[wrong_type],[reason],[wrong_description],[complaint_status],[date],[create_time] order by [inspected_person] desc) as row from ( SELECT [check_date] ,[checker] ,[inspected_person] ,[secondary_rework] ,[type] ,[project] ,[project_name] ,[NID] ,[wrong_type] ,[reason] ,[wrong_description] ,[complaint_status] ,[date] ,[create_time] ,[AssigneeId] FROM [DV_report].[dbo].[miss] as a left join [User] as b on a.[AssigneeId]=b.id where date>='${start}' and date<='${end}' and complaint_status='申诉后' and wrong_type not in ('无','建议') and inspected_person not in('DL001','DL002') ) c) d where d.row = '1' UNION select * from ( select * ,row_number() over(partition by [check_date],[checker],[inspected_person],[secondary_rework],[type],[project],[project_name],[NID],[wrong_type],[reason],[wrong_description],[complaint_status],[date],[create_time] order by [inspected_person] desc) as row from ( SELECT [check_date] ,[checker] ,[secondary_rework] as [inspected_person] ,'' as [secondary_rework] ,[type] ,[project] ,[project_name] ,[NID] ,[wrong_type] ,[reason] ,[wrong_description] ,[complaint_status] ,[date] ,[create_time] ,[AssigneeId] FROM [DV_report].[dbo].[miss] as a left join [User] as b on a.[AssigneeId]=b.id where date>='${start}' and date<='${end}' and complaint_status='申诉后' and wrong_type = '网络问题' and [reason] = '状态错误' and [secondary_rework] is not null and [secondary_rework] !='' and inspected_person not in('DL001','DL002') ) c) d where d.row = '1' )as a left join [User] as b on a.[AssigneeId]=b.id WHERE b.leader_name IS NOT NULL and b.IsActive = '1' group by b.[leader_name],[inspected_person],wrong_type,b.Departure_date order by [inspected_person] 帮我将这段代码转换为postgre格式语言

SELECT b."leader_name", "inspected_person", "wrong_type", b."Departure_date", count(*) as miss数量 FROM ( SELECT * FROM ( SELECT *, row_number() OVER(PARTITION BY "check_date","checker",...

以下语句中sql = """ SELECT date_z, SUM(cnt) FROM ( SELECT id_person, date_z, COUNT() + IFNULL(nn, 0) AS cnt FROM ( SELECT id_person, date_z, date_finish FROM luzhi_jilu_all WHERE id_person = %s AND (date_z = date_finish OR date_finish IS NULL) ) AS t1 LEFT JOIN ( SELECT id_person, date_finish, COUNT() AS nn FROM luzhi_jilu_all GROUP BY id_person, date_finish ) AS t2 ON t1.id_person = t2.id_person AND t1.date_z = t2.date_finish GROUP BY id_person, date_z ) AS t3 GROUP BY date_z ORDER BY date_z DESC """ params = (id_person,) cs.execute(sql, params) jg = cs.fetchall() 出现以下错误pymysql.err.InternalError: (1052, "Column 'id_person' in field list is ambiguous"),请检查并修改

SELECT t1.id_person, date_z, COUNT(*) + IFNULL(nn, 0) AS cnt FROM ( SELECT id_person, date_z, date_finish FROM luzhi_jilu_all WHERE id_person = %s AND (date_z = date_finish OR date_finish IS NULL...

请修改：SELECT date, COUNT(*) AS new FROM ( SELECT user_id, MIN(date) AS first_login_date FROM login GROUP BY user_id ) AS first_login WHERE first_login_date = date GROUP BY date ORDER BY date ASC;

SELECT login_date, COUNT(*) AS new FROM ( SELECT user_id, MIN(login_date) AS first_login_date FROM login GROUP BY user_id ) AS first_login WHERE first_login_date = login_date GROUP BY login_date ...

select order_type,count_time,count(1) from external_store_order t where count_type=1 and count_time>sysdate-1 group by order_type;

这是一条 SQL 语句，作用是查询 external_store_order 表中在最近一天内，按照 order_type 分组统计每个订单类型的数量。具体含义如下： - select：查询语句的关键字，表示要查询指定的列。 - order_type,count_...

以下建表语句正确的有（） 2分 CREATE TABLE table_b AS SELECT * FROM table_a; CREATE TABLE table_b STORED as ORC_TRANSACTION AS SELECT * FROM table_a; CREATE TABLE table_b STORED as TEXTFILE AS SELECT * FROM table_a; CREATE TABLE table_b STORED as HOLODESK AS SELECT * FROM table_a;

- CREATE TABLE table_b STORED as TEXTFILE AS SELECT * FROM table_a; 该语句是正确的。它创建了一个名为table_b的表，并且将表table_a中的数据以TEXTFILE格式存储到新表中。 - CREATE TABLE table_b STORED as ...

可否优化以下语句sql = "select date_j,count() from jiaoban_day group by date_j order by date_j desc" co.to_sql(sql) jg = cs.fetchall() data = {} for j in jg: sql = "select date_j,count() from personnal_note where id_person='{0}' and date_j='{1}'".format(id_person,j[0]) co.to_sql(sql) n = cs.fetchone() data[j[0]] = str(j[1]+n[0])

sql = "SELECT jiaoban_day.date_j, COUNT(*) AS cnt1, COUNT(personnal_note.date_j) AS cnt2 \ FROM jiaoban_day \ LEFT JOIN personnal_note \ ON jiaoban_day.date_j = personnal_note.date_j \ AND ...

with t as( select t1.video_id,COUNT(case when DATEDIFF(SECOND,t1.start_time,t1.end_time)>=t2.duration then 1 end) complete_qty, count(1) total_qty,COUNT(IIF(if_like=1,1,null)) like_qty,COUNT(IIF(if_retweet=1,1,null)) zf_qty, COUNT(comment_id) pl_qty,max(CAST(end_time as date)) v_last_playdate from tb_user_video_log t1 join tb_video_info t2 on t1.video_id=t2.video_id where DATEDIFF(DAY,release_time,(select max(end_time) from tb_user_video_log))<=29 group by t1.video_id ) select t.video_id,CAST((100complete_qty1.0/total_qty+5like_qty+3pl_qty+2zf_qty)1.0 /((DATEDIFF(DAY,v_last_playdate,(select max(end_time) from tb_user_video_log)))+1) as int) from t 优化以上sql

4. 将 FROM t, (SELECT MAX(end_time) as max_end_time FROM tb_user_video_log) AS max_end 用于将两个查询结果合并。这些优化措施可以提高查询的性能和可读性。请注意，具体的优化效果还需要考虑数据库的索引和...

SELECT item_type_id, COUNT( * ) AS typeCount FROM prosper_item_base_info WHERE item_id IN ( '1116704448291274752', '1116704567245930496', '1116704728433033216', '1116704644853137408', '1116704823471767552', '1116704898314928128', '1116705032100642816', '1116704823471767552', '1116704898314928128' ) ORDER BY typeCount DESC 如何让他的返回的结果typeCount数量为9

SELECT item_type_id, COUNT(*) AS typeCount FROM prosper_item_base_info WHERE item_id IN ('1116704448291274752', '1116704567245930496', '1116704728433033216', '1116704644853137408', '...

以下python语句sql = """ SELECT date_z, COUNT() + IFNULL(nn, 0) FROM ( SELECT id_person, date_z, date_finish FROM luzhi_jilu_all WHERE id_person = %s AND (date_z = date_finish OR date_finish IS NULL) ) AS t1 LEFT JOIN ( SELECT id_person, date_finish, COUNT() AS nn FROM luzhi_jilu_all GROUP BY id_person, date_finish ) AS t2 ON t1.id_person = t2.id_person AND t1.date_z = t2.date_finish GROUP BY date_z ORDER BY date_z DESC """ params = (id_person,) cs.execute(sql, params) jg = cs.fetchall()提示出现以下错误pymysql.err.InternalError: (1055, "Expression #2 of SELECT list is not in GROUP BY clause and contains nonaggregated column 't2.nn' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by"),请检查错误,并修改

SELECT id_person, date_finish, COUNT(*) AS nn FROM luzhi_jilu_all GROUP BY id_person, date_finish ) AS t2 ON t1.id_person = t2.id_person AND t1.date_z = t2.date_finish GROUP BY date_z ORDER BY ...

$sql_num = "select count(id) as count from news";

$sql_num = "select count(id) as count from news"; $result = mysqli_query($conn, $sql_num); // 关闭数据库连接 mysqli_close($conn); // 处理查询结果 if (mysqli_num_rows($result) > 0) { $row = mysqli_...

select pro_c_id from ( select pro_c_id, count(pro_c_id) as cnt1, cnt2 from ( select pro_c_id, pro_pif_id, ( select count(*) from ( select pro_pif_id from property where pro_type = 1 group by pro_pif_id having count(distinct(pro_c_id)) > 2 ) as t1 ) as cnt2 from property as p natural join ( select pro_pif_id from property where pro_type = 1 group by pro_pif_id having count(distinct(pro_c_id)) > 2 ) as t2 where pro_type = 1 order by pro_c_id ) as t3 group by pro_c_id ) as t4 where cnt1 = cnt2

这是一个SQL语句，用于查询拥有至少三个不同产品的公司的ID。具体的查询条件是：首先从属性表中选择属性类型为1的记录，并计算每个产品被多少个公司所拥有，将结果作为t1表。然后从t1表中选择拥有至少三个不同公司...

以下的mysql语句如何在id_person和date_z上建立索引,并修改以下语句,以提高查询速度sql = """select date_d,count(*) from luzhi_jilu_all where id_person='{}' group by date_d order by date_d desc """.format(id_person)

SELECT date_d, COUNT(*) FROM luzhi_jilu_all WHERE id_person='{}' GROUP BY date_d ORDER BY date_d DESC 请将大括号{}替换为实际的id_person值。这个查询语句能够在id_person和date_z上建立的索引的...

leftjoin中打印sql为什么会输出SELECT COUNT(*) AS think_count FROM

在执行第一个查询时，会自动生成一个SELECT COUNT(*) AS think_count FROM的SQL语句，用于统计符合条件的记录总数。这个SQL语句的目的是为了方便进行分页等操作。然后，在执行第二个查询时，会生成实际的数据...

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$sql_num = "select count(id) as count from news";

以下的mysql语句如何在id_person和date_z上建立索引,并修改以下语句,以提高查询速度sql = """select date_d,count(*) from luzhi_jilu_all where id_person='{}' group by date_d order by date_d desc """.format(id_person)

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