bitset求一的位数

bitset的求一位数可以通过bitset中的count()函数来实现。count()函数返回bitset中值为1的位数。下面是一个使用bitset求一位数的示例代码：

#include <iostream>
#include <bitset>

int main() {
    std::bitset<8> b(0b11011011); // 假设bitset中的二进制数为11011011
    int count = b.count();
    std::cout << "bitset中值为1的位数为：" << count << std::endl;
    
    return 0;
}

输出结果为：

bitset中值为1的位数为：6

因此，上述示例代码中bitset的求一位数为6。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
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