把这段代码从matlab转换为c#%交叉变换 %输入变量：pop：父代种群，pc：交叉的概率 %输出变量：newpop：交叉后的种群 function [new_pop] = crossover(pop, pc) [px,~] = size(pop); % 判断路径点数是奇数或偶数 parity = mod(px, 2); new_pop = {}; for i = 1:2:px-1 singal_now_pop = pop{i, 1}; singal_next_pop = pop{i+1, 1}; [lia, lib] = ismember(singal_now_pop, singal_next_pop); [~, n] = find(lia == 1); [~, m] = size(n); if (rand < pc) && (m >= 3) % 生成一个2-m-1之间的随机数 r = round(rand(1,1)*(m-3)) +2; crossover_index1 = n(1, r); crossover_index2 = lib(crossover_index1); new_pop{i, 1} = [singal_now_pop(1:crossover_index1), singal_next_pop(crossover_index2+1:end)]; new_pop{i+1, 1} = [singal_next_pop(1:crossover_index2), singal_now_pop(crossover_index1+1:end)]; else new_pop{i, 1} =singal_now_pop; new_pop{i+1, 1} = singal_next_pop; end if parity == 1 new_pop{px, 1} = pop{px, 1}; end end

以下是C#代码实现：

public List<List<int>> Crossover(List<List<int>> pop, double pc)
{
    int px = pop.Count;
    int parity = px % 2;
    List<List<int>> new_pop = new List<List<int>>();

    for (int i = 0; i < px - 1; i += 2)
    {
        List<int> singal_now_pop = new List<int>(pop[i]);
        List<int> singal_next_pop = new List<int>(pop[i + 1]);

        IEnumerable<int> common = singal_now_pop.Intersect(singal_next_pop);
        List<int> n = new List<int>();
        foreach (int c in common)
        {
            int index = singal_now_pop.IndexOf(c);
            if (index >= 0)
            {
                n.Add(index);
            }
        }

        if ((new Random().NextDouble() < pc) && (n.Count >= 3))
        {
            int r = new Random().Next(2, n.Count - 1);
            int crossover_index1 = n[r];
            int crossover_index2 = singal_next_pop.IndexOf(singal_now_pop[crossover_index1]);

            List<int> child1 = new List<int>(singal_now_pop.GetRange(0, crossover_index1));
            child1.AddRange(singal_next_pop.GetRange(crossover_index2 + 1, singal_next_pop.Count - crossover_index2 - 1));

            List<int> child2 = new List<int>(singal_next_pop.GetRange(0, crossover_index2));
            child2.AddRange(singal_now_pop.GetRange(crossover_index1 + 1, singal_now_pop.Count - crossover_index1 - 1));

            new_pop.Add(child1);
            new_pop.Add(child2);
        }
        else
        {
            new_pop.Add(singal_now_pop);
            new_pop.Add(singal_next_pop);
        }
    }

    if (parity == 1)
    {
        new_pop.Add(pop[px - 1]);
    }

    return new_pop;
}

注意，在C#中，需要使用`List<List<int>>`来表示二维数组。另外，C#中的随机数生成需要使用`System.Random`类，而不是`rand`函数。`Intersect`方法可以用来获取两个列表的交集，而`GetRange`方法可以用来获取列表的一部分。