enum eDirection { STOP = 0, LEFT, RIGHT, UP, DOWN }; eDirection dir;void Setup(){ srand(time(NULL)); dir = STOP; 这三行代码是什么意思
时间: 2024-04-21 10:25:19 浏览: 17
这三行代码的意思是:
1. 定义了一个枚举类型eDirection,其中包含五个枚举值:STOP、LEFT、RIGHT、UP、DOWN,分别对应静止、向左、向右、向上、向下的方向。
2. 声明了一个eDirection类型的变量dir,用来保存当前方向。
3. 在Setup()函数中,通过调用srand()函数来初始化随机数生成器,使得后续的随机数生成不会重复。然后将dir的初始值设置为STOP,表示初始状态下不需要移动。
相关问题
用conio,stdio,time,Windows头文件写的贪吃蛇代码,可运行
很抱歉,我是一个语言模型AI,并不能提供代码运行的功能。不过我可以为您提供一个简单的贪吃蛇代码供参考。
```c++
#include <stdio.h>
#include <conio.h>
#include <time.h>
#include <windows.h>
const int width = 20;
const int height = 20;
int x, y, fruitX, fruitY, score;
int tailX[100], tailY[100];
int nTail;
enum eDirection { STOP = 0, LEFT, RIGHT, UP, DOWN };
eDirection dir;
void Setup(){
srand(time(NULL));
dir = STOP;
x = width / 2;
y = height / 2;
fruitX = rand() % width;
fruitY = rand() % height;
score = 0;
}
void Draw(){
system("cls");
for (int i = 0; i < width + 2; i++)
printf("#");
printf("\n");
for (int i = 0; i < height; i++){
for (int j = 0; j < width; j++){
if (j == 0)
printf("#");
if (i == y && j == x)
printf("O");
else if (i == fruitY && j == fruitX)
printf("F");
else{
bool print = false;
for (int k = 0; k < nTail; k++){
if (tailX[k] == j && tailY[k] == i){
printf("o");
print = true;
}
}
if (!print)
printf(" ");
}
if (j == width - 1)
printf("#");
}
printf("\n");
}
for (int i = 0; i < width + 2; i++)
printf("#");
printf("\n");
printf("Score:%d\n", score);
}
void Input(){
if (_kbhit()){
switch (_getch()){
case 'a':
dir = LEFT;
break;
case 'd':
dir = RIGHT;
break;
case 'w':
dir = UP;
break;
case 's':
dir = DOWN;
break;
case 'x':
exit(0);
}
}
}
void Logic(){
int prevX = tailX[0];
int prevY = tailY[0];
int prev2X, prev2Y;
tailX[0] = x;
tailY[0] = y;
for (int i = 1; i < nTail; i++){
prev2X = tailX[i];
prev2Y = tailY[i];
tailX[i] = prevX;
tailY[i] = prevY;
prevX = prev2X;
prevY = prev2Y;
}
switch (dir){
case LEFT:
x--;
break;
case RIGHT:
x++;
break;
case UP:
y--;
break;
case DOWN:
y++;
break;
default:
break;
}
if (x >= width) x = 0; else if (x < 0) x = width - 1;
if (y >= height) y = 0; else if (y < 0) y = height - 1;
for (int i = 0; i < nTail; i++){
if (tailX[i] == x && tailY[i] == y)
dir = STOP;
}
if (x == fruitX && y == fruitY){
score += 10;
fruitX = rand() % width;
fruitY = rand() % height;
nTail++;
}
}
int main(){
Setup();
while (dir != STOP){
Draw();
Input();
Logic();
Sleep(100);
}
return 0;
}
```
这是一个简单的贪吃蛇代码,使用了C语言的头文件和库函数。因为你没有提供具体的运行情境,所以我不能确定这段代码是否符合你的要求。如果你有任何问题,可以随时问我。
帮我写一个贪吃蛇c++代码
当然可以,以下是一个简单的贪吃蛇C代码:
```c
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <time.h>
#define WIDTH 40
#define HEIGHT 20
int x, y, fruitX, fruitY, score;
int tailX[100], tailY[100], nTail;
enum eDirection { STOP = 0, LEFT, RIGHT, UP, DOWN };
enum eDirection dir;
void Setup() {
srand(time(NULL));
dir = STOP;
x = WIDTH / 2;
y = HEIGHT / 2;
fruitX = rand() % WIDTH;
fruitY = rand() % HEIGHT;
score = 0;
}
void Draw() {
system("cls");
for (int i = 0; i < WIDTH + 2; i++)
printf("#");
printf("\n");
for (int i = 0; i < HEIGHT; i++) {
for (int j = 0; j < WIDTH; j++) {
if (j == 0)
printf("#");
if (i == y && j == x)
printf("O");
else if (i == fruitY && j == fruitX)
printf("F");
else {
int print = 0;
for (int k = 0; k < nTail; k++) {
if (tailX[k] == j && tailY[k] == i) {
printf("o");
print = 1;
}
}
if (!print)
printf(" ");
}
if (j == WIDTH - 1)
printf("#");
}
printf("\n");
}
for (int i = 0; i < WIDTH + 2; i++)
printf("#");
printf("\n");
printf("Score: %d\n", score);
}
void Input() {
if (_kbhit()) {
switch (_getch()) {
case 'a':
dir = LEFT;
break;
case 'd':
dir = RIGHT;
break;
case 'w':
dir = UP;
break;
case 's':
dir = DOWN;
break;
case 'x':
dir = STOP;
break;
}
}
}
void Logic() {
int prevX = tailX[0];
int prevY = tailY[0];
int prev2X, prev2Y;
tailX[0] = x;
tailY[0] = y;
for (int i = 1; i < nTail; i++) {
prev2X = tailX[i];
prev2Y = tailY[i];
tailX[i] = prevX;
tailY[i] = prevY;
prevX = prev2X;
prevY = prev2Y;
}
switch (dir) {
case LEFT:
x--;
break;
case RIGHT:
x++;
break;
case UP:
y--;
break;
case DOWN:
y++;
break;
default:
break;
}
if (x >= WIDTH) x = 0; else if (x < 0) x = WIDTH - 1;
if (y >= HEIGHT) y = 0; else if (y < 0) y = HEIGHT - 1;
for (int i = 0; i < nTail; i++)
if (tailX[i] == x && tailY[i] == y)
dir = STOP;
if (x == fruitX && y == fruitY) {
score += 10;
fruitX = rand() % WIDTH;
fruitY = rand() % HEIGHT;
nTail++;
}
}
int main() {
Setup();
while (dir != STOP) {
Draw();
Input();
Logic();
}
return 0;
}
```
好了,现在你可以和这个AI玩贪吃蛇了!
相关推荐
![rar](https://img-home.csdnimg.cn/images/20210720083606.png)
![zip](https://img-home.csdnimg.cn/images/20210720083736.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)