18Breakageratecalculation non-broken roofing 18Breakageratecalculation broken roofing 18Breakageratecalculation non-broken roofing 18Breakageratecalculation non-broken roofing 18Breakageratecalculation non-broken roofing 18Breakageratecalculation non-broken roofing 18Breakageratecalculation courtyard 18Breakageratecalculation non-broken roofing把txt文件的标签按顺序排序并对应0：non-broken roofing,1:broken roofing,2:courtyard代码

假设txt文件名为labels.txt，可以使用以下代码将文件中的标签按顺序排序并对应为0：non-broken roofing, 1:broken roofing, 2:courtyard：

with open('labels.txt', 'r') as f:
    labels = f.read().split()

sorted_labels = sorted(labels)

label_dict = {'non-broken roofing': 0, 'broken roofing': 1, 'courtyard': 2}

label_list = [label_dict[label] for label in sorted_labels]

print(label_list)

该代码会将文件中的标签读取到列表labels中，排序后将其对应为0：non-broken roofing, 1:broken roofing, 2:courtyard，并将其存储在列表label_list中。最后打印label_list。