python七段数码管计时

以下是Python实现七段数码管计时的代码：

import time

# 数码管字典
digit_dict = {
    '0': ['1111110', '1010000', '1010000', '1010000', '1010000', '1010000', '1111110'],
    '1': ['0100100', '1101100', '0001000', '0001000', '0001000', '0001000', '1111110'],
    '2': ['1111110', '0000010', '0000010', '1111110', '1000000', '1000000', '1111110'],
    '3': ['1111110', '0000010', '0000010', '1111110', '0000010', '0000010', '1111110'],
    '4': ['1010000', '1010000', '1010000', '1111110', '0000010', '0000010', '0000010'],
    '5': ['1111110', '1000000', '1000000', '1111110', '0000010', '0000010', '1111110'],
    '6': ['1111110', '1000000', '1000000', '1111110', '1010000', '1010000', '1111110'],
    '7': ['1111110', '0000010', '0000010', '0000100', '0001000', '0010000', '0100000'],
    '8': ['1111110', '1010000', '1010000', '1111110', '1010000', '1010000', '1111110'],
    '9': ['1111110', '1010000', '1010000', '1111110', '0000010', '0000010', '1111110']
}

# 获取当前时间
def get_time():
    return time.strftime('%H%M%S', time.localtime(time.time()))

# 显示数码管
def show_digit(digit):
    for i in range(7):
        for j in range(7):
            if digit[i][j] == '1':
                print('*', end='')
            else:
                print(' ', end='')
        print()

# 主函数
def main():
    while True:
        # 获取当前时间
        current_time = get_time()
        # 分离出时、分、秒
        hour = current_time[0:2]
        minute = current_time[2:4]
        second = current_time[4:6]
        # 显示时、分、秒
        show_digit(digit_dict[hour[0]])
        show_digit(digit_dict[hour[1]])
        print('       ', end='')
        show_digit(digit_dict[minute[0]])
        show_digit(digit_dict[minute[1]])
        print('       ', end='')
        show_digit(digit_dict[second[0]])
        show_digit(digit_dict[second[1]])
        # 暂停一秒
        time.sleep(1)
        # 清屏
        print('\033c', end='')

if __name__ == '__main__':
    main()