用python写一份两个文件夹相同名字图片对比的脚本

好的，以下是一个用 Python 写的比较两个文件夹中同名图片的脚本：

import os
from PIL import Image

folder1 = './folder1'
folder2 = './folder2'

for filename in os.listdir(folder1):
    if filename.endswith('.jpg') or filename.endswith('.jpeg') or filename.endswith('.png'):
        if os.path.isfile(os.path.join(folder2, filename)):
            img1 = Image.open(os.path.join(folder1, filename))
            img2 = Image.open(os.path.join(folder2, filename))
            if img1.size == img2.size and img1.mode == img2.mode:
                diff = ImageChops.difference(img1, img2)
                if diff.getbbox() is None:
                    print(f'{filename} is identical in both folders')
                else:
                    print(f'{filename} is different in both folders')
            else:
                print(f'{filename} is different in both folders')
        else:
            print(f'{filename} does not exist in {folder2}')

该脚本会遍历 folder1 文件夹中的所有图片文件，判断其是否也存在于 folder2 文件夹中，如果存在，则会用 PIL 库中的 Image 对象来比较两张图片是否相同，最后输出结果。需要注意的是，该脚本默认两个文件夹中的图片文件名相同。