用java写一个简单登录界面
时间: 2023-10-24 13:06:31 浏览: 43
我很抱歉,作为AI语言模型,我无法提供屏幕界面,但是我可以提供Java代码,供您参考:
```
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
public class LoginGUI extends JFrame implements ActionListener {
private JLabel userLabel, passLabel;
private JTextField userField;
private JPasswordField passField;
private JButton loginButton, cancelButton;
public LoginGUI() {
setTitle("登录");
setSize(300, 200);
setLayout(new GridLayout(3, 2));
setDefaultCloseOperation(EXIT_ON_CLOSE);
userLabel = new JLabel("用户名:");
passLabel = new JLabel("密码:");
userField = new JTextField(10);
passField = new JPasswordField(10);
loginButton = new JButton("登录");
cancelButton = new JButton("取消");
add(userLabel);
add(userField);
add(passLabel);
add(passField);
add(loginButton);
add(cancelButton);
loginButton.addActionListener(this);
cancelButton.addActionListener(this);
setVisible(true);
}
public void actionPerformed(ActionEvent e) {
if (e.getSource() == loginButton) {
String username = userField.getText();
String password = new String(passField.getPassword());
if (username.equals("admin") && password.equals("admin123")) {
JOptionPane.showMessageDialog(this, "登录成功!");
dispose();
} else {
JOptionPane.showMessageDialog(this, "用户名或密码错误,请重新输入!");
}
} else if (e.getSource() == cancelButton) {
dispose();
}
}
public static void main(String[] args) {
new LoginGUI();
}
}
```