查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩create table Student(s_id varchar(100),s_name varchar(200),s_birth date,s_sex varchar(100)); create table Course(c_id varchar(100),c_name varchar(200),t_id varchar(100)); insert into Course values('01','语文','02'); insert into Course values('02','数学','01'); insert into Course values('03','英语','03'); insert into student values('01','赵雷','1990-01-01','男'); insert into student values('02','钱电','1990-12-21','男'); insert into student values('03','孙风','1990-05-20','男'); insert into student values('04','李云','1990-08-06','男'); insert into student values('05','周梅','1991-12-01','女'); insert into student values('06','吴兰','1992-03-01','女'); insert into student values('07','郑竹','1989-07-01','女'); insert into student values('08','王菊','1990-01-20','女'); create table Teacher(t_id varchar(100),t_name varchar(100)); create table Score (s_id varchar(100), c_id varchar(100),s_score int); insert into score values('01','01',80); insert into score values('01','02',90); insert into score values('01','03',99); insert into score values('02','01',70); insert into score values('02','02',60); insert into score values('02','03',80); insert into score values('03','01',80); insert into score values('03','02',80); insert into score values('03','03',80); insert into score values('04','01',50); insert into score values('04','02',30); insert into score values('04','03',20); insert into score values('05','01',76); insert into score values('05','02',87); insert into teacher values('01','张三'); insert into teacher values('02','李四'); insert into teacher values('03','王五');

我可以回答这个问题。查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩的 SQL 语句如下：

SELECT s_id, s_name, AVG(s_score) AS avg_score
FROM student, score
WHERE student.s_id = score.s_id
GROUP BY student.s_id, student.s_name
HAVING AVG(s_score) >= 60;